Energy created by falling object

This is also equal to the kinetic energy at the end of the fall, which is 1/2 mv^2. Therefore, 1/2 mv^2 = mg\Delta h.In summary, the amount of joules created when a 1.36 kg weight falls 0.1524 meters can be calculated by using the equation 1/2 mv^2 = mg\Delta h, where m is the mass of the object, g is the acceleration due to gravity, and \Delta h is the change in elevation. In this particular case, the calculation results in 2.032 joules of energy. However, it is important to note that this is a conversion from gravitational potential energy to kinetic energy
  • #1
Greg E
1
0
If there is a 1.36 kg weight falling .1524 meters,
how many joules are created when the object reachs the end of the .1524 meters. How do you calculate this?
I came up with 2.032 joules which is .20723 kg meters which I think is enough power to lift 1.36 kg .1524 meters which is the same as where I started and that cannot be correct because a falling object has more power than the same object standing still.
Thanks,
Greg
 
Physics news on Phys.org
  • #2
This seems like a homework problem from Introductory Physics.

However, an object falling implies falling due to gravity. What one has is a conversion/transformation from gravitational potential energy to kinetic energy.

Taking the acceleration of gravity to be constant, the change in gravitational potential energy is mg[itex]\Delta h[/itex], where [itex]\Delta h[/itex] is the change in elevation.
 
  • #3


I would like to clarify that energy is not created but rather transformed from one form to another. In this case, the potential energy of the falling object is transformed into kinetic energy as it falls. The amount of energy produced can be calculated using the formula E = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height the object falls (0.1524 m in this case).

Using the given values, we can calculate the energy produced as 1.36 kg x 9.8 m/s^2 x 0.1524 m = 2.032 joules.

It is important to note that this is the maximum potential energy that can be produced by the falling object and not all of it will be converted into kinetic energy. Some energy will be lost due to air resistance and other factors.

Furthermore, the amount of energy required to lift an object is equal to the weight of the object multiplied by the height it is lifted. In this case, lifting a 1.36 kg object by 0.1524 meters would require 1.36 kg x 9.8 m/s^2 x 0.1524 m = 2.032 joules of energy, which is the same amount of energy produced by the falling object.

Therefore, it is not incorrect to say that the energy produced by a falling object is enough to lift the same object to the same height, as long as all other factors are taken into consideration.
 

1. How does gravity create energy when an object falls?

When an object is lifted off the ground, it gains potential energy due to its position in the Earth's gravitational field. As the object falls, this potential energy is converted into kinetic energy, which is the energy of motion.

2. Is the energy created by a falling object constant?

No, the energy created by a falling object is not constant. It depends on the mass and height of the object, as well as other factors such as air resistance. As the object falls, its potential energy decreases while its kinetic energy increases.

3. Can the energy created by a falling object be harnessed?

Yes, the energy created by a falling object can be harnessed through various methods such as hydroelectric power, where the kinetic energy of falling water is converted into electricity. However, the efficiency of this process is limited by factors such as the height and flow rate of the water.

4. What happens to the energy created by a falling object when it hits the ground?

When a falling object hits the ground, the energy is transferred to the ground and surrounding objects in the form of heat, sound, and deformation. Some of the energy may also be lost due to factors such as air resistance and friction.

5. Can the energy created by a falling object be used to power a device?

Yes, the energy created by a falling object can be used to power a device through methods such as using gravity to turn a turbine or generate electricity. This is commonly seen in devices such as grandfather clocks and pendulum clocks.

Similar threads

  • Introductory Physics Homework Help
Replies
15
Views
340
  • Introductory Physics Homework Help
Replies
12
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
13
Views
935
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Classical Physics
2
Replies
61
Views
1K
  • Classical Physics
Replies
29
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
2K
Back
Top