- #1
noboost4you
- 61
- 0
This is the problem: find the area of the region bounded by the curves f(x) = x^2 + 2 and g(x) = 4 - x^2 on the interval [-2,2]
I did the whole integral from -2 to 2 with (4-x^2) - (x^2 + 2) dx because the graph of g(x) is on top between the region bounded. But from my drawing, the points where the curves meet and shaded in the area is between -1 and 1. What am I doing wrong?
My answer came to be -8/3 and area can't be negative. Any suggestions?
Thanks
I did the whole integral from -2 to 2 with (4-x^2) - (x^2 + 2) dx because the graph of g(x) is on top between the region bounded. But from my drawing, the points where the curves meet and shaded in the area is between -1 and 1. What am I doing wrong?
My answer came to be -8/3 and area can't be negative. Any suggestions?
Thanks