Particle disturbance by passing EM wave reveals momentum of EM wave?

In summary: JakeSo you're saying an EM wave has two parts: A physical wavefront that oscillates and a non-physical wave function that gives a probability of where the photon will manifest?No, that's incorrect. The "wavefront" of an EM wave is the physical part. There is no "non-physical wave function" associated with a classical EM wave. In classical EM, the fields are described by Maxwell's equations, which are differential equations that describe how the fields vary in space and time. There is no probabilistic aspect to it.In quantum mechanics, the photon's wave function is a mathematical construct that describes the probability of finding the photon at a given location at a given time. It is not a physical wave in
  • #1
jaketodd
Gold Member
508
21
Hey guys and gals,

Here are two of a vast sea of sources that say a passing EM wave will disturb charged particles:

http://books.google.com/books?id=jC4...age&q=&f=false
"...a wave passing over a row of electrons; the arrows indicate the magnitude and direction of the electromagnetic force the wave exerts on the charges."

http://webpages.ursinus.edu/dnagy/ph...cRadiation.pdf
"As an electromagnetic wave passes a charged particle, the Electromagnetic Waves Electric field produces a strong upward force on a
electric field at the particle varies with time, dragging the particle back and forth along the direction of the field."

So we know that momentum can be transferred to particles without the EM wave collapsing to a particle and a collision happening.

My question: If you know how far away the EM wave is from the particle and you measured how much the particle is disturbed by it, would that reveal the momentum of the whole EM wave/photon?

Thanks in advance,

Jake
 
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  • #2
Anyone?
 
  • #3
I'm not sure I understand your question, why it is puzzling, and why it is in the quantum physics forum.

EM wave is NOT the "wavefunction" that is the solution to the Schrodinger equation/Hamiltonian. So there is no "collapse". Secondly, RF signal is used in ALL particle accelerating structure as the mechanism to accelerate charged particles. So this isn't anything new, or surprising.

Thirdly, do you know about Compton scattering?

And finally, what does "how far the EM wave is from the particle" has anything to do with this? If the EM wave is NOT interacting with the particle, nothing will happen to that particle. If you are talking about single-photon interaction, then refer to the Compton scattering I mentioned earlier.

Zz.
 
  • #4
I guess you didn't look at the sources I cited. They clearly say that an EM wave can be a distance away from a charged particle and effect it.
 
  • #5
jaketodd said:
I guess you didn't look at the sources I cited. They clearly say that an EM wave can be a distance away from a charged particle and effect it.
I can't get those links to work, but are you sure they didn't say that the source of the EM wave can be a distance away?
 
  • #6
Ya, now I can't get the links to work either. They used to work. I assure you they are from credible sources. Do a google search for yourself if you don't believe me. And yes, the plethora of sources I found talk about an EM wave passing close to a charged particle but not touching it.
 
  • #7
jaketodd said:
And yes, the plethora of sources I found talk about an EM wave passing close to a charged particle but not touching it.
That makes no sense to me, so I'd like to see a reference.

Edit: FYI, you posted the links incorrectly. Try again. (They are incomplete.)
 
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  • #8
jaketodd said:
I guess you didn't look at the sources I cited. They clearly say that an EM wave can be a distance away from a charged particle and effect it.

I don't read the second quote as saying that. I think you're misinterpreting the word "passes" in this context. It's not supposed to imply that the wave "misses" the particle.

The first quote is probably the same sort of thing, but the phrasing "passing over" is a bit strange. I think it's just sloppy language, but I'd have to see it in the context of the entire page, to be sure.

I think you may have been misled by the very common diagrams such as this one into thinking that an electromagnetic wave is confined to a line, sort of like a wave along a stretched string. It actually fills a volume of space. See this post and the attached diagram for a more realistic picture.
 
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  • #9
Well I guess those links only last awhile. I found the source again, copied the link to my clipboard, cleared my cookies, shut down all IE windows, opened a new one, pasted in the link and it worked. So here it is again: http://books.google.com/books?id=jC...wave passing over a row of electrons"&f=false

Please examine it and if I have misinterpreted it, let me change my question: Can you know the momentum of an EM wave by how much it disturbs charged particles without the EM wave collapsing to a photon?

And no, I don't think an EM wave travels in a line, I know it has a curved wavefront that expands laterally as it propagates.

Thanks guys.

Jake
 
  • #10
jaketodd said:
without the EM wave collapsing to a photon?

To repeat what ZapperZ wrote in post #3, classical electromagnetic waves are not the same thing as the photon's QM wave function. Classical electromagnetic waves correspond to the net effect of bazillions of photons, and do not "collapse." If you're in a situation where there is just a single photon, I don't think you can meaningfully use the classical electromagnetic field.
 
  • #11
jtbell said:
To repeat what ZapperZ wrote in post #3, classical electromagnetic waves are not the same thing as the photon's QM wave function. Classical electromagnetic waves correspond to the net effect of bazillions of photons, and do not "collapse." If you're in a situation where there is just a single photon, I don't think you can meaningfully use the classical electromagnetic field.

So you're saying an EM wave has two parts: A physical wavefront that oscillates and a non-physical wave function that gives a probability of where the photon will manifest? I thought that the two were one in the same. And why wouldn't one EM wave (the wave nature of one photon) have electromagnetic properties? Please explain.

And please let's get back to the question: Can the momentum of an EM wave, touching or just near a charged particle, be determined by the movement of the charged particle?

Thank you!
 
  • #12
jaketodd said:
So you're saying an EM wave has two parts: A physical wavefront that oscillates and a non-physical wave function that gives a probability of where the photon will manifest? I thought that the two were one in the same.

This is the fatal flaw in your argument. A wavefunction that is the solution to Schrodinger equation is not physical. It "lives" in configuration space. It is not the "EM wave" that is the solution of Maxwell equation.

Zz.
 
  • #13
ZapperZ said:
This is the fatal flaw in your argument. A wavefunction that is the solution to Schrodinger equation is not physical. It "lives" in configuration space. It is not the "EM wave" that is the solution of Maxwell equation.

Zz.

So you're saying that the momentum of an EM wave, touching or just near a charged particle, can't be determined by the movement of the charged particle?
 
  • #14
jaketodd said:
So you're saying that the momentum of an EM wave, touching or just near a charged particle, can't be determined by the movement of the charged particle?

What does that have anything to do with :

ZapperZ said:
This is the fatal flaw in your argument. A wavefunction that is the solution to Schrodinger equation is not physical. It "lives" in configuration space. It is not the "EM wave" that is the solution of Maxwell equation.

?

This is a weird thread going in many directions at once.

Zz.
 
  • #15


Ok, I wasn't sure what you were saying. You said "fatal flaw in your argument" so I thought that you were saying that the answer is no. But I wasn't sure so I asked. All I want to know is, which is the title of this thread, "Particle disturbance by passing EM wave reveals momentum of EM wave?"
 
  • #16


jaketodd said:
Ok, I wasn't sure what you were saying. You said "fatal flaw in your argument" so I thought that you were saying that the answer is no. But I wasn't sure so I asked. All I want to know is, which is the title of this thread, "Particle disturbance by passing EM wave reveals momentum of EM wave?"

.. and like I asked earlier, I have no idea why this in the quantum physics forum, since this is basically a classical E&M question, since you keep insisting on "EM wave" picture.

So read this about momentum of a classical EM wave, since that is what you're asking.

http://electron9.phys.utk.edu/phys135d/modules/m10/emwaves.htm

Now, from there, try to justify if, without the presence of such wave, you will be able to transfer momentum to a charge particle. We're not talking about some exotic QM phenomenon like the Aharonov-Bohm effect here, are we?

Zz.
 
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  • #17


ZapperZ said:
.. and like I asked earlier, I have no idea why this in the quantum physics forum, since this is basically a classical E&M question, since you keep insisting on "EM wave" picture.

So read this about momentum of a classical EM wave, since that is what you're asking.

http://electron9.phys.utk.edu/phys135d/modules/m10/emwaves.htm

Now, from there, try to justify if, without the presence of such wave, you will be able to transfer momentum to a charge particle. We're not talking about some exotic QM phenomenon like the Aharonov-Bohm effect here, are we?

Zz.

So it's a yes?
 
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  • #19
ZapperZ said:
No.

Zz.


EM waves don't disturb charged particles? Didn't we agree that if the wave touches them then they will be disturbed? Oh you're saying you can't tell how much momentum the whole wave has from that disturbance even if you know how much of the wave touched the charged particle and the width of the wavefront?
 
  • #20
jaketodd said:
EM waves don't disturb charged particles? Didn't we agree that if the wave touches them then they will be disturbed? Oh you're saying you can't tell how much momentum the whole wave has from that disturbance even if you know how much of the wave touched the charged particle and the width of the wavefront?

Who said anything about that?

YOUR SCENARIO that you are asking has the EM wave somewhere else! What is "just near"? Next door? In the next cavity?

If you are explicit in what you are asking, I will be explicit in my answers. If you simply type 4 words, I'll response in kind.

I work with particle accelerators in which the RF field IS the accelerating field. It would be silly of me to not know that EM wave can impart energy and momentum to charged particles.

BTW, the link that I gave you tells you EXACTLY how to calculate the momentum of a EM wave! So what is the problem now?

Zz.
 
  • #21
Sorry. Thank you.
 
  • #22
But can an EM wave's momentum be known by how much it disturbs a charged particle?
 

1. What is an EM wave?

An EM wave, short for electromagnetic wave, is a type of wave that is created by the oscillation of electric and magnetic fields. It is a form of energy that can travel through space and does not require a medium to propagate.

2. How does an EM wave interact with particles?

When an EM wave passes through a medium, it creates a disturbance in the particles that make up that medium. This disturbance causes the particles to vibrate, which in turn creates an electric field that interacts with the EM wave. The strength of this interaction reveals the momentum of the EM wave.

3. What is the significance of knowing the momentum of an EM wave?

Knowing the momentum of an EM wave is important in understanding how it interacts with matter. It can also provide insights into the properties and behavior of the EM wave itself, and can be used in various applications such as telecommunications and energy transmission.

4. How is the momentum of an EM wave measured through particle disturbance?

The momentum of an EM wave can be measured through the observation of the particle disturbance it creates. By analyzing the amplitude and frequency of the particle vibrations, scientists can determine the strength of the electric field and thus calculate the momentum of the EM wave.

5. Are there any practical implications of studying particle disturbance by passing EM waves?

Yes, there are many practical implications of studying particle disturbance by passing EM waves. For example, this phenomenon is used in technologies such as radar and wireless communication. It also helps us better understand the behavior of light and other EM waves, which has led to advancements in fields such as optics and astronomy.

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