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jegues said:Is this what you mean?
xcvxcvvc said:Yes, except you're not calculating the equivalent resistance correctly.
jegues said:What am I doing wrong?
Sorry if you're help seems somewhat "hopeless" but I am indeed trying to understand this.
EDIT: Doh, 5//10 + 15 = 18.3
xcvxcvvc said:yes :) You may want to run through your Ith calculation again until you get the right value. You'll know now, because by using it, you'll calculate the same Vth as you just did.
jegues said:Well wait...
If I'm looking for my Ith and I know my Vth and Rth, can't I simply apply Ohm's Law?
Ith = Vth/Rth = 10/18.3 = 0.546A
?
All you have to do is sum the total resistance in a loop and multiply it by the current of that loop minus the sum of any shared resistances multiplied by the current that is sharing the resistor plus any additional voltages (from voltage sources).
jegues said:Thank you for all your help and the explanation of mesh analysis xcvxcvvc!
I've got a few questions.
These seems to work flawlessly and is very easy to follow. However, the confusion that remains is the confusion within my intution. I've drawn a picture to show you where I've become confused.
I think you may have explained this in your post, but it's still not clear to me how the signs on the 10ohm resistors(I put it in red in the 2nd mesh analysis) are not interchanged.
Other than that everything makes sense!
Thanks in advance!
we defined the current as going from up to down
jegues said:When did we do this? Was this implicit when I labeled the polarities of my 10 ohm resistor?
This is where I always get confused between polarities and direction of current.
berkeman said:Resistors don't have polarities. Voltages have polarities and currents have directions. Your figure and equations look okay to me. With mesh analysis, you just pick the loop current directions (usually clockwise as you have used), and write out the KVL equations.
Thevenin's Theorem is a fundamental concept in circuit analysis that states that any linear electrical network with voltage and current sources can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. This equivalent circuit is known as Thevenin Equivalent Circuit.
Thevenin's Theorem is applied by breaking down a complex circuit into a simpler equivalent circuit, which can be solved using simple circuit analysis techniques. This simplifies the process of analyzing complex circuits and provides an efficient method for determining the voltage and current at any point in the circuit.
Thevenin's resistance is the equivalent resistance of a circuit as seen from two terminals. It is calculated by removing all the voltage and current sources in the circuit and determining the resistance between the two terminals. The value of Thevenin's resistance is used to calculate the equivalent voltage source in the Thevenin Equivalent Circuit.
Thevenin's Theorem simplifies the analysis of complex circuits by reducing them to a simpler equivalent circuit consisting of a single voltage source and a single resistor. This helps in calculating the voltage and current at any point in the circuit, without having to solve complex equations. Thevenin's Theorem also provides a more efficient method for determining the maximum power transfer in a circuit.
Thevenin's Theorem can only be applied to linear circuits, which means that the components in the circuit must have a linear relationship between voltage and current. It also assumes that the circuit is in a steady-state condition and does not take into account the effects of non-linear components such as diodes. Additionally, Thevenin's Theorem is only applicable to circuits with a single source, and cannot be used for circuits with multiple sources.