Calculating Flee's Acceleration After Take-Off

[N2]

Hello,
A flee jumps a horizontal distance of 0.035m with an angle of 70°.
I calculated the startspeed, v0, to 0.73m/s (projectile motion) - but then I am asked the following:
"What is the flee's average acceleration, if the startspeed is achieved after a take-off on 8.0 * 10^(-4) m"
How should i interpret the this situation?( As the startspeed being zero, and the flee accelerating to point where the speed, v0, is achieved? sounds odd to me)

 

[HallsofIvy]

Hello,
A flee jumps a horizontal distance of 0.035m with an angle of 70°.
I calculated the startspeed, v0, to 0.73m/s (projectile motion) - but then I am asked the following:
"What is the flee's average acceleration, if the startspeed is achieved after a take-off on 8.0 * 10^(-4) m"
How should i interpret the this situation?( As the startspeed being zero, and the flee accelerating to point where the speed, v0, is achieved? sounds odd to me)

If you assume a constant acceleration, a (the average acceleration), then the final speed is at= 0.73m/s and the distance is (1/2)at²= 8.0 x10^-4m. Solve those two equations to find a.

 

[quicknote]

Hello there,

I would interpret this situation as follows: The flee starts at rest (zero velocity) and accelerates until it reaches a starting speed of 0.73m/s. The distance it travels during this acceleration is 8.0 * 10^(-4) m. This means that the flee's average acceleration can be calculated using the following formula: a = (vf - vi)/t, where vf is the final velocity (0.73m/s), vi is the initial velocity (0m/s), and t is the time it takes to achieve this velocity (which can be calculated using the distance and initial velocity).

Using this formula, we can calculate the flee's average acceleration to be 912.5 m/s^2. This may seem like a high acceleration, but keep in mind that the flee is very small and light, so it is able to achieve this acceleration quickly. I hope this helps to clarify the situation for you. Let me know if you have any further questions.