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Perpendicular components of the perpendicular plane |
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| Jun30-12, 11:48 AM | #1 |
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Perpendicular components of the perpendicular plane
What does the the cross product of two acceleration vectors do?
(a cross ar) = 0 where a =axi + ayj + azk and ar = arxi + aryj + arzk (a cross ar)x = ay*arz - az*ary (a cross ar)y = az*arx - ax*arz (a cross ar)z = ax*ary - ay*arx It gives the perpendicular components of each. In the perpendicular plane of "ar" what happens if you set the the cross product equal to an angle on that perpendicular plane. To give you control of which way the "ar" will execute: (a cross ar) = ap where ap = apxi +apyj + apzk ap is in the perpendicular plane of ar. |
| Jul1-12, 08:40 AM | #2 |
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I think I gave you the reason why no one replied to your thread. |
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