Defining a thermodynamic system completely

In summary: N2 are not given... What if you only have data for liquid or solid? Then you're limited to only two molar fractions.
  • #1
Urmi Roy
753
1
So I read somewhere that if we know u(s,v) i.e. internal energy as a function of entropy and specific volume, we can find all other thermodynamics quantities on earth, like temperature, pressure, Gibb's free energy from it.

However, is this true if we have u as a function of just any two thermodynamic properties?

Also. if we know Gibb's free energy/ Helmoltz energy in terms of any 2 quantities, can we similarly find all other thermodynamic properties from it? In case there is a chemical reaction going on, then I guess we need to define 2 such parameters, right?
 
Science news on Phys.org
  • #2
No, knowing internal energy as a function of other set of quantities is not as informative as knowing ##U(S,V)##.

For example, the energy of ideal gas is ##U = c_V nRT## (depends on temperature and molar number only), but from this we cannot find the equation of state ##pV = nRT##. However, from relation ##U(S,V)## we can find this equation of state. For this function, see Callen's book

Callen H.B., Thermodynamics And An Introduction To Thermostatistics, 2ed., Wiley, 1985

or the Wikipedia page

https://en.wikipedia.org/wiki/Ideal_gas

section "Thermodynamic Potentials" towards the end. The Gibbs energy provides complete thermodynamic description only if expressed as function of pressure and temperature (and molar numbers).
 
  • Like
Likes 1 person
  • #3
Well can I ask a question which is indirectly related to this? (I'm just trying to correlate things I've learned in this thermo course this semester...).
So the question is...at the triple point for a given pure substance, where we know the temperature and pressure, how many parameters are required to know exactly the fraction of each phase that exists? For example, if you know u(s,v), it would not be enough, right? You'd require another parameter...could that be any thermodynamic parameter?
 
  • #4
Urmi Roy said:
So the question is...at the triple point for a given pure substance, where we know the temperature and pressure, how many parameters are required to know exactly the fraction of each phase that exists?
Since there are three phases, we need to know two molar fractions, for example ##\frac{n_{solid}}{n}##, ##\frac{n_{liquid}}{n}##. The third molar fraction can be derived from these two, since

$$
n_{solid} + n_{liquid} + n_{gaseous} = n.
$$

(divide by ##n## and express the third fraction).

For example, if you know u(s,v), it would not be enough, right? You'd require another parameter...could that be any thermodynamic parameter?

I'm not sure what you mean. What is u(s,v)? You mean ##U(S,V)## (total energy, entropy and volume), or ##u(s,v)## (energy, entropy and volume per mole) ?
 
  • #5
Sorry for the delay in replying! I just finished my final maths exam. So I mean specific internal energy i.e. energy, entropy and volume per mole/kg. Maybe I could explain the question by going back to what you said:
Jano L. said:
Since there are three phases, we need to know two molar fractions, for example ##\frac{n_{solid}}{n}##, ##\frac{n_{liquid}}{n}##. The third molar fraction can be derived from these two, since

$$
n_{solid} + n_{liquid} + n_{gaseous} = n.
$$

(divide by ##n## and express the third fraction).

You're saying we need to know 2 mole fractions.I get that. But what if you have no way of measuring that...Wouldn't it be enough to know (as an example) the specific internal energy and specific enthalpy of the system and hence, from that knowledge (and the knowledge of the internal energy & enthalpy of each phase, from data books) determine the mole fractions?
 
  • #6
Wouldn't it be enough to know (as an example) the specific internal energy and specific enthalpy of the system and hence, from that knowledge (and the knowledge of the internal energy & enthalpy of each phase, from data books) determine the mole fractions?

What do you mean by specific internal energy and enthalpy of the whole system? The quantities
$$
u = \frac{U}{N}
$$
and
$$
h = \frac{H}{N}
$$
where ##N## is the total molar number?

How would you get to know these for two-phase system? Measuring molar fractions of each phase seems so much easier.

But if we somehow knew ##u,h## for the composed system, we could solve the equations

$$
Nu = u_1N_1 + u_2 N_2
$$

$$
Nh = h_1N_1 + h_2 N_2
$$

$$
N_1 + N_2 = N
$$

(##1## for solid, ##2## for liquid) for ##N_1,N_2, N##, to get both molar fractions and even the total number of molecules.
 
  • #7
Jano L. said:
What do you mean by specific internal energy and enthalpy of the whole system? The quantities
$$
u = \frac{U}{N}
$$
and
$$
h = \frac{H}{N}
$$
where ##N## is the total molar number?

How would you get to know these for two-phase system? Measuring molar fractions of each phase seems so much easier.

But if we somehow knew ##u,h## for the composed system, we could solve the equations

$$
Nu = u_1N_1 + u_2 N_2
$$

$$
Nh = h_1N_1 + h_2 N_2
$$

$$
N_1 + N_2 = N
$$

(##1## for solid, ##2## for liquid) for ##N_1,N_2, N##, to get both molar fractions and even the total number of molecules.

Yes, the definition of specific quantities is what you've mentioned at the top of your post. I'm talking about it in the perspective of problem-solving on exams...

But you've mentioned only N1 and N2 ...we were talking about the triple point, so there will be N1, N2 and N3. Still, we have 3 equations and 3 unknowns, so I suppose its ok.
 
  • #8
Hm, mathematically it seems that way. But I do not see physical motivation behind such calculation.
 

1. What is a thermodynamic system?

A thermodynamic system is a portion of the universe that is being studied and analyzed in terms of its energy and matter interactions. It can be a single object, a group of objects, or a specific region in space.

2. What does it mean to define a thermodynamic system completely?

To define a thermodynamic system completely means to specify all the necessary parameters and variables that describe the system, such as its volume, pressure, temperature, and composition. This allows for a thorough understanding of the system's behavior and properties.

3. Why is it important to define a thermodynamic system completely?

Defining a thermodynamic system completely is important because it allows for accurate predictions and calculations of its behavior. It also helps in identifying the boundaries and interactions of the system with its surroundings, which is crucial in the study of thermodynamics.

4. How is a thermodynamic system defined?

A thermodynamic system is defined by specifying its physical boundaries, the type and amount of matter it contains, and the energy that can enter or leave the system. This information is used to determine the state of the system and its properties.

5. Can a thermodynamic system change?

Yes, a thermodynamic system can change by exchanging matter or energy with its surroundings. This can result in changes in the system's state and properties, leading to different thermodynamic processes such as heating, cooling, and phase transitions.

Similar threads

  • Thermodynamics
Replies
3
Views
821
Replies
11
Views
297
Replies
5
Views
2K
Replies
3
Views
989
  • Thermodynamics
Replies
4
Views
1K
  • Thermodynamics
Replies
3
Views
1K
Replies
2
Views
462
Replies
15
Views
1K
Replies
13
Views
1K
Replies
4
Views
1K
Back
Top