Vector or Not Vector: Analysis of Magnitude & Direction

  • Thread starter BobbyFluffyPric
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In summary: This is a subtle but important distinction.Yep. If the context is Euclidean space, then you have the usual notion of magnitude... and you can get by the "magnitude and direction" description. In intro courses, that context is usually implied. But if one starts trying to question things, it's good to start with the real definitions.
  • #36
I can't, for the life of me, understand why you think that any vector can be transformed from one coordinate system to another when such a transformation may be entirely meaningless for a particuar kind of vector. E.g. I meant for the matrices to be ten dimensional, not 10x10
(In case you were thinking about 4-D spacetime). As I said, I'm looking for such an example right now and will post it when I find it. But such a criteria never exist for a vector space where such a critera always exists for geometrical vectors.

A good example which comes to mind now is the vector space whose elements belong to Fourier series, i.e. a sequance of sines and cosines in increasing frequency which can approximate any function of a given interval. How would you transform these elements to another coordinate system when, even when you can write down something that lokks like a transformation (God only knows what that transformation looks like or means) such a transformation is meaningless.

Pete
 
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  • #37
pmb_phy said:
How would you derive the transformation properties for vector spaces? There are vector spaces in which no such requirement need be defined or cannot be defined.

Pete

In any vector space there exist an infinite number of possible bases. "Transformation" properties are transformation that take a vector written in one basis to the same vector written in a different basis.
 
  • #38
You folks really don't get the part about the transformation properties that I speak of do you?

In any case I believe I understand the problem now. First off - I believe I was wrong [ know. Hard to believe, right? :) ]. A geometric vector is an element of a vector space. Adding on the requirement that it satisfies certain transformation properties makes it a geometric vector.

Good think I stuck it out with this of shoot of this thread or I never would have known the solution to my delema. However this doesn't at all mean that I'm right now. I'm checking double checking my assumptions off the web and I'll get back to you.

Pete
 
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  • #39
pmb_phy said:
However you never know. To be a good physicist one must keep an open mind so I e-mailed Ohanian again and asked him about this. Due to our eight years of exchanging e-mail with the man I've grown a very deep repspect for him. So we'll see what happens. I have no need to be right, just a need to know what is right.

Pete

Make sure you ask him this specific question:

Must a vector [whether from linear algebra or geometry] be an element of a vector space?
 
  • #40
robphy said:
Make sure you ask him this specific question:

Must a vector [whether from linear algebra or geometry] be an element of a vector space?

It doesn't matter Rob. I've sent it already and I'm really not disagreeing with you now. But I'll PM the response (if I get one) to you if you'd like?

Pete
 
  • #41
pmb_phy said:
Adding on the requirement that it satisfies certain transformation properties makes it a geometric vector.
It's not the tangent vector (or cotangent vector, or tensor, or whichever thing we're looking at) that transforms -- it's the coordinate representation of that vector that transforms when you change coordinates. The whole point of the "geometric" adjective is that the vector itself is entirely independent of your choice of coordinates.
 
  • #42
Hurkyl said:
It's not the tangent vector (or cotangent vector, or tensor, or whichever thing we're looking at) that transforms -- it's the coordinate representation of that vector that transforms when you change coordinates. The whole point of the "geometric" adjective is that the vector itself is entirely independent of your choice of coordinates.
First off I never referred to a tangent vectors. I kept it simple by keeping it in a flat space and using the position vector as a prototype of a generalized vector. And when I said that Adding on the requirement that it satisfies certain transformation properties makes it a geometric vector. I meant that the components must obey the given transformation rule. And I know what I meant since I've been over with this with folks for 8 years now. I think you simply read me wrong. Now let's say we let this thread lay to rest. You win. Rejoice! Peace out my friend. Please don't destroy your victory by attempting to re-educate me about things I know all too well. Okay? :)

Oh. By the way. If I were you then I'd read page 40 of MTW.

Pete
 
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