
#1
Oct2013, 04:39 AM

P: 9

Hi all,
I'm learning how to solve redox equations. I found the algebraic method to solve equations such as this one: Fe[itex]^{2+}[/itex] + Cr[itex]_{2}[/itex]O[itex]_{7}[/itex][itex]^{2}[/itex] +H[itex]^{+}[/itex][itex]\rightarrow[/itex] Fe[itex]^{3+}[/itex] + Cr[itex]^{3+}[/itex] + H[itex]_{2}[/itex]0 and i was able to solve it. What I don't see is how to use that algebraic method to solve an equation without superscripts; since it doesn't allow you to balance the charges, right? like for example: NaOH + Cr(OH)[itex]_{3}[/itex] + NaClO[itex]\rightarrow[/itex] Na[itex]_{2}[/itex]CrO[itex]_{4}[/itex] +NaCl + H[itex]_{2}[/itex]O Thanks for your help. 



#2
Oct2313, 04:15 AM

Admin
P: 22,708

If everything is neutral (on both sides of the reaction) there is no need to separately balance the charge. But you can always write an additional identity
[tex]0\times a_1 + 0\times a_2 + ... = 0\times b_1 + 0\times b_2 + ...[/tex] (assuming a_{i} are stoichiometric coefficients on the LHS of the equation, and b_{i} are coefficients on the RHS). Compare ChemBuddy lecture on the algebraic method of reaction equation balancing  it shows how to balance both equations with charged and uncharged species. Use [sub][/sub] and [sup][/sup] tags to format the formulas, don't mix normal text with LaTeX, it is not guaranteed to work OK. 


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