Functions, operator => eigenfunction, eigenvalue

In summary: The Attempt at a SolutionThis is what i got for the first function:http://img391.imageshack.us/img391/4461/38657444ih2.jpg The next step is to solve left part of the equation, and than compare it to the right part.The question arises, how to solve that equation?I tried simplifying left part of an equation in mathcad, and I gothttp://img391.imageshack.us/img391/1897/28095157bm3.jpg Next question from that part, is if I am doing it right, how to compare those parts
  • #1
sundriedtomato
14
0
[SOLVED] Functions, operator => eigenfunction, eigenvalue

Homework Statement


Show, that functions
f1 = A*sin([tex]\theta[/tex])exp[i[tex]\phi[/tex]] and
f2 = B(3cos[tex]^{2}[/tex]([tex]\theta[/tex]) - 1) A,B - constants
are eigenfunctions of an operator
http://img358.imageshack.us/img358/3406/98211270ob1.jpg [Broken]
and find eigenvalues


The Attempt at a Solution


This is what i got for the first function:
http://img391.imageshack.us/img391/4461/38657444ih2.jpg [Broken]

The next step is to solve left part of the equation, and than compare it to the right part.

The question arises, how to solve that equation?

I tried simplifying left part of an equation in mathcad, and I got
http://img391.imageshack.us/img391/1897/28095157bm3.jpg [Broken]

Next question from that part, is if I am doing it right, how to compare those parts, and answer a question - weather this function is an eigenfunction of an operator?

Thank You in advance, and I am constantly near computer and waiting for suggestions.
 
Last edited by a moderator:
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  • #2
Your eigen operator has partial derivatives wrt to [itex]\theta[/itex] and [itex]\phi[/itex]. When you operate it on your given eigen function, you should get back your original function multiplied by a scaling factor which is your eigenvalue.
 
  • #3
Yes, Thank You, but how do I calculate that? May I ask for instructions on how to calculate that left part of an equation? Is the result I got is correct?
 
  • #4
sundriedtomato said:
Yes, Thank You, but how do I calculate that? May I ask for instructions on how to calculate that left part of an equation? Is the result I got is correct?

Just go ahead and apply the derivatives! It's that simple. (btw, I don't know what you entered in mathcad but what it gave you is wrong).

all you have to do is to apply the derivatives
 
  • #5
sundriedtomato said:
Yes, Thank You, but how do I calculate that? May I ask for instructions on how to calculate that left part of an equation? Is the result I got is correct?

For the first term, what you have to calculate is

[tex] \frac{1}{sin \theta} \frac{\partial}{\partial \theta} ( sin \theta ~\frac{\partial}{ \partial \theta} (A sin \theta} e^{i \phi}}) ) [/tex]
 
  • #6
I will give it a try right know. Thank You.
 
  • #7
So, after proper calculations, the result is
http://img76.imageshack.us/img76/3385/38806746cn9.jpg [Broken]

Is this one correct?

I posted an image of what I am given, and as far as I know, differentiation sign usually is placed before the function?
I just don't get it - to what parts of an equation do underlined derivatives belong t?
http://img511.imageshack.us/img511/9895/22kn1.jpg [Broken]

Thank You.
 
Last edited by a moderator:
  • #8
The part in brackets is an "operator"... every incomplete differentiation sign (ie, without anything to differentiate) operates on whatever is "multiplied" to it.

For example, the d/d(theta) is your image also operates on A*sin(theta)*exp(i*phi), because when you open the bracket, it gets to differentiate that term.

Eg. (the d's are partial)
[d/dx + d/dy]*x*y^2 = y^2 + 2*y*x
 
  • #9
sundriedtomato said:
Yes, Thank You, but how do I calculate that? May I ask for instructions on how to calculate that left part of an equation? Is the result I got is correct?
Just operate it on the function. They are simple partial derivatives, I won't take much time to solve. Just a little patience for the initial steps. I tried your problem and many terms get canceled out and you get the solution correctly. You don't need mathcad to do it.
 
  • #10
Thank You Reshma! I already managed to solve it correctly, and find eigenvalues as well.
For the case with the first function : a = 2h^2, and for the case with second function b = 6h^2. The problem was initially in understanding how to apply operator properly. Once example have been given, and operator properties reanalyzed - problem got solved in like 10 minutes (with putting it all on a paper as well). Thank You everybody who took part in this one!
 

1. What is a function?

A function is a mathematical concept that describes the relationship between two variables, where each input value (also known as the independent variable) is associated with exactly one output value (also known as the dependent variable).

2. What is an operator?

An operator is a symbol or function that performs a specific mathematical operation on one or more input values to produce an output value.

3. What is an eigenfunction?

An eigenfunction is a special type of function that, when acted upon by a linear operator, results in a scalar multiple of itself. This scalar multiple is known as the eigenvalue of the eigenfunction.

4. What is an eigenvalue?

An eigenvalue is a scalar value that represents the magnitude of the effect of a linear operator on an eigenfunction. It is often used to describe the behavior of a system or process in physics, engineering, and other sciences.

5. How are eigenfunctions and eigenvalues used in science?

Eigenfunctions and eigenvalues are important concepts in many areas of science, particularly in quantum mechanics and linear algebra. They are used to describe the behavior of systems and processes, and to solve complex mathematical equations and problems.

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