A simple Atwood's machine (conservation of energy)

In summary, Atwood's machine uses two masses, m1 and m2. The speed of the two masses is 5.0 m/s at the end of 3.0 s. At that instant, the kinetic energy of the system is 90 J and each mass has moved a distance of 7.5 m.
  • #1
Seiya
43
1
Tipler5 6.P.060.] A simple Atwood's machine uses two masses, m1 and m2 (Figure 6-38). Starting from rest, the speed of the two masses is 5.0 m/s at the end of 3.0 s. At that instant, the kinetic energy of the system is 90 J and each mass has moved a distance of 7.5 m. Determine the values of m1 and m2.


Okay this problem is giving me a hard time.. i don't know why i must be missing something...

Here is what I have done, i said that at the beginning KE is 0 and PE must be 90 J.

Once it falls down the 7.5m the KE is 90J therefore the PE is 0J.

There is the "3 seconds time" that is there and i know I am supposed to use it somehow but i could use some help here... i calculated the acceleration with that but fail to see whre i could use it right now...

here are my equations... for the beginning:

initial
total energy =90 = PEi + KEi = 7.5(9.8)(m1+m2) + 0

final
total eneryg = 90 = PEf + KEf = ((m1+m2)(v^2))/2

this homework problem is due in 3 hours, its the last problem i have to do , just a hint would help a lot, thanks guys
 
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  • #2
why does the PE have to be 0 at the end of three seconds? it doesn't say that the masses have come to a halt doest. one of the masses has to have some PE because it is moving in th positive y direction right.

the total kinetic energy is 90 joules, there is also some PE being made here, from the one mass moving up, the system is transferring some KE to PE
 
  • #3
you are right, i assumed all of the PE converted to KE... damn..

illl write my new equations now, thank you!


alright is this better?

KEf+PEf=PEi+KEi

KEi = 0
KEf= 90J

KEf=1/2((m1+m2)v^2)

90= PEi - PEf

90=(m1+m2)(g)(h) - ((m1(g)(-7.5))+(m2(g)(7.5)))

a=v/t
a=1.667

d=(at^2)/2

update:
im going to put the lowest height as height 0 and PE 0, where they start from ast 7.5 and the highest height one as 15... is this right? what should i do next?
 
Last edited:
  • #4
wee i tried it like i stated above and it worked out :) awesome, thanks for the hint mathmike

answers are:

m1 is 4.212 Kg
m2 is 2.988 Kg

yay! :P
 
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1. What is an Atwood's machine?

An Atwood's machine is a simple mechanical device that consists of two masses connected by a string or rope that passes over a pulley. It is used to illustrate the principles of conservation of energy and Newton's laws of motion.

2. How does an Atwood's machine demonstrate conservation of energy?

In an Atwood's machine, the total energy (kinetic + potential) of the system remains constant. As one mass moves down, the other moves up with the same speed, and the potential energy is converted to kinetic energy. This demonstrates the principle of conservation of energy, where energy cannot be created or destroyed but can only be converted from one form to another.

3. What is the significance of an Atwood's machine in physics?

An Atwood's machine is a simple yet effective way to demonstrate the principles of conservation of energy and Newton's laws of motion. It helps to understand the relationship between forces, acceleration, and mass, and how energy is conserved in a mechanical system.

4. How does the mass ratio affect an Atwood's machine?

The mass ratio, which is the ratio between the two masses in an Atwood's machine, affects the acceleration of the system. The larger the mass ratio, the greater the acceleration of the system. This is because the difference in the weights of the masses creates an unbalanced force, causing the system to accelerate.

5. Can an Atwood's machine be used to generate energy?

No, an Atwood's machine cannot be used to generate energy. The total energy of the system remains constant, and any energy converted from potential to kinetic energy is ultimately dissipated as heat due to factors such as friction. Therefore, an Atwood's machine cannot be used as a perpetual motion machine or a source of free energy.

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