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Radwa Kamal
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Although the electronegativity difference between sodium and hydrogen in NaH is less than 1.7 , it is ionic bond WHY??
Radwa Kamal said:Thanx 4 enrichin me by this info in fact my study is somehow limited because am still in high school I didn't study QM calculations
Radwa Kamal said:Thanx 4 enrichin me by this info in fact my study is somehow limited because am still in high school I didn't study QM calculations
The electronegativity difference between sodium (Na) and hydrogen (H) in NaH is 1.93. This value is calculated by subtracting the electronegativity of hydrogen (2.20) from the electronegativity of sodium (0.93).
The large electronegativity difference between sodium and hydrogen results in an ionic bond in NaH. This means that sodium will transfer its electron to hydrogen, creating a positively charged sodium ion and a negatively charged hydrogen ion.
The electronegativity difference between elements is important because it determines the type of bond that will form between them. In the case of NaH, the large electronegativity difference results in an ionic bond, while a smaller difference would result in a covalent bond.
The electronegativity difference between sodium and hydrogen in NaH is relatively high compared to other ionic compounds. For example, the electronegativity difference between sodium and chlorine in NaCl is 2.10, while the difference between sodium and oxygen in Na2O is 3.13.
The electronegativity values for sodium and hydrogen are determined by the number of protons and their distance from the nucleus in each atom. In NaH, the large difference in electronegativity values between sodium (0.93) and hydrogen (2.20) is due to the large difference in their atomic structures.