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Homework Statement
8. (II) A car can decelrate at -4.80 m/s^2 without skidding when coming to rest on a level road. What would its decelration be if the road were inclined at 13 degrees uphill? Assume the same static friction force.
Homework Equations
Ffr = MuFn
F = ma
The Attempt at a Solution
Ok I don't see what I'm doing wrong here.
The first think I did was find Mu on the horizontal surface
F = ma = Ffr = Mu m g
mass canceled out
a = Mu g
Mu therefore = a/g
Mu = 4.8/9.8 = .4898
Then for the up hill
F = ma = Fgx + Ffr
= mg sin (theta) + Mu mg cos (theta)
mass canceled out
a = g sin (theta) + Mu g cos (theta)
a = 9.8 sin (13) + .4898 (9.8) cos (13) = 6.9 m/s^2 then it would be negative 6.9 m/s^2