- #1
subopolois
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Homework Statement
how do i find the roots of this: x^2-(2-1)x+(3-i)=0
Homework Equations
-b+-sqrtb^2-4ac/2a (quardaric equation)
Defennder said:What have you done so far?
And why did you write it as "(2-1)x" and not "x"? Did you mean "(2-i)x" instead? Why can't you just apply the formula?
subopolois said:and what formula would that be?
Complex numbers are numbers that contain both a real part and an imaginary part. They are represented as a + bi, where a is the real part and bi is the imaginary part (with i being the imaginary unit).
To find the roots of an equation with complex numbers, you can use the quadratic formula or factor the equation. The roots will be in the form of a + bi, where a and b are real numbers.
Yes, complex numbers can have multiple roots. For example, the equation x^3 - 8 = 0 has three roots: 2, -1+√3i, and -1-√3i.
Complex numbers can be represented as points on the complex plane, where the horizontal axis represents the real part and the vertical axis represents the imaginary part. This allows for visualizing complex numbers and their operations.
Yes, the roots of an equation with complex numbers have a few special properties. The product of the roots is equal to the constant term divided by the leading coefficient, and the sum of the roots is equal to the opposite of the coefficient of the second highest degree term divided by the leading coefficient.