- #1
Tom McCurdy
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Help: Max Rage of a Projectile Uphill
I am working on some physics on a site I found and was wondering if I could tap into some of the wisdom that seems embeded in the forums.
The problem I am working on is problem three from
http://www.math.rutgers.edu/~costin/291/w3.pdf
All I am interested in doing is show how to optimize the uphill range.
I have been doing some inital attacking but don't seem to be getting anywhere. I know the answer from that site [tex] tan 2 \alpha = -cot \theta [/tex]
Here is some of the stuff that I have been starting out doing
[tex] y/x=tan\theta [/tex]
[tex] y= x tan \theta [/tex]
[tex] R/x= sec \theta [/tex]
[tex] R = (Vot+1/2at^2) sec \theta [/tex]
[tex] \frac {v^2-V_o^2}{{2*9.8}}=x [/tex]
I am not very sure on how many of these are true because I haven't had time fully to reexamine them and I was trying to force things together that probably need to be placed. I will continue to work on this problem as I just started but If anyone can sucessfully show me how to come up with
I am working on some physics on a site I found and was wondering if I could tap into some of the wisdom that seems embeded in the forums.
The problem I am working on is problem three from
http://www.math.rutgers.edu/~costin/291/w3.pdf
All I am interested in doing is show how to optimize the uphill range.
I have been doing some inital attacking but don't seem to be getting anywhere. I know the answer from that site [tex] tan 2 \alpha = -cot \theta [/tex]
Here is some of the stuff that I have been starting out doing
[tex] y/x=tan\theta [/tex]
[tex] y= x tan \theta [/tex]
[tex] R/x= sec \theta [/tex]
[tex] R = (Vot+1/2at^2) sec \theta [/tex]
[tex] \frac {v^2-V_o^2}{{2*9.8}}=x [/tex]
I am not very sure on how many of these are true because I haven't had time fully to reexamine them and I was trying to force things together that probably need to be placed. I will continue to work on this problem as I just started but If anyone can sucessfully show me how to come up with
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