flashmanbs said:
flashmanbs said:my Q explain why the CFSE =-24Dq+2p at d6 not =-24Dq+3p?
like u see in fig. if we put the 6`th electron we have 3 paring set so we was should add 3p to the CFSE why we count them as 2P?
Q is a parameter used in crystal field theory to describe the interaction between a metal ion and its surrounding ligands. It represents the strength of the ligand field and is calculated as the difference between the energy of the metal ion in the ligand field and its energy in a hypothetical spherical field.
The value of Q directly affects the splitting energy in crystal field theory. A higher Q value indicates a stronger ligand field, leading to a larger splitting energy between the d orbitals of the metal ion. Conversely, a lower Q value indicates a weaker ligand field and a smaller splitting energy.
Yes, Q can be negative in crystal field theory. This occurs when the ligands have a higher energy than the metal ion in a hypothetical spherical field. A negative Q value indicates a weak ligand field, resulting in a smaller splitting energy between the d orbitals.
Q plays a crucial role in determining the color of transition metal complexes. The energy difference between the d orbitals, which is determined by Q, corresponds to the wavelength of light absorbed by the complex. Therefore, a higher Q value results in a higher energy difference and a shorter wavelength, leading to a more intense color.
The value of Q can be influenced by several factors such as the nature and arrangement of the ligands, the oxidation state of the metal ion, and the geometry of the complex. Additionally, the presence of other nearby metal ions or solvent molecules can also affect the value of Q.