Reduced Circumference: Schwarzschild vs Kerr Metric

In summary, the r-coordinate in the Schwarzschild metric represents the reduced circumference, but in the Kerr metric it does not. It is unclear what the r-coordinate represents in the Kerr metric, but a possible explanation is that it may be related to a change in coordinates that results in the reduced circumference for the phi coordinate.
  • #1
Moore1879
21
0
Okay, I understand that the r-coordinate in the Schwarzschild metric represents the reduce circumference. My problem is that the r-coordinate in the Kerr metric is NOT the reduced circumference! What is it? Somebody, please answer this as quickly and as painlessly as possible!
Thank You
 
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  • #2
Right, it is not. What is it? Sorry, I don’t know... I guess that if you make a coordinate change in a way that you get [tex]\inline{R(r)^2 d{\phi}^2}[/tex] then [tex]\inline{R}[/tex] will be the reduced circumference for [tex]\inline{\phi}}[/tex]. May be this can give you a hint about a possible physical meaning of [tex]\inline{r}[/tex].
 

1. What is the Schwarzschild metric and how does it relate to reduced circumference?

The Schwarzschild metric is a mathematical representation of the curvature of spacetime around a non-rotating, spherically symmetric mass. The reduced circumference is a measure of the distance around the mass, taking into account the effects of gravity. In the Schwarzschild metric, the reduced circumference is equal to the circumference in flat space divided by the square root of 1-2GM/rc2, where G is the gravitational constant, M is the mass of the object, and c is the speed of light.

2. How does the Kerr metric differ from the Schwarzschild metric in terms of reduced circumference?

The Kerr metric is a more complex mathematical representation of the curvature of spacetime around a rotating, axially symmetric mass. Unlike the Schwarzschild metric, the Kerr metric includes terms for the rotation of the mass. This leads to a different formula for the reduced circumference, which takes into account the effects of both gravity and rotation.

3. Why is the Kerr metric important for understanding black holes?

The Kerr metric is important for understanding black holes because it accurately describes the spacetime around rotating black holes, which are thought to be the most common type of black hole in the universe. This metric allows scientists to calculate the properties of rotating black holes, such as their event horizons and ergospheres, and make predictions about their behavior.

4. How do the reduced circumference formulas for Schwarzschild and Kerr metrics differ?

The reduced circumference formula for the Schwarzschild metric is equal to the circumference in flat space divided by the square root of 1-2GM/rc2, while the reduced circumference formula for the Kerr metric is equal to the circumference in flat space divided by the square root of [(r2+a2)2-a2Δsin2θ]/Δ, where a is the angular momentum per unit mass of the rotating black hole and Δ=r2-2Mr+a2.

5. Can the reduced circumference formulas for Schwarzschild and Kerr metrics be used to measure the actual circumference of a black hole?

No, the reduced circumference formulas for Schwarzschild and Kerr metrics are theoretical calculations and cannot be used to measure the actual circumference of a black hole. This is because the curvature of spacetime around a black hole is so extreme that traditional measurements of distance and circumference do not apply. These formulas are valuable for understanding and predicting the behavior of black holes, but they cannot be used for direct measurement.

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