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Work and Energy

 
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Dec6-12, 06:57 PM   #18
 

Work and Energy


Quote by benrocks1 View Post
Oh so the kinetic energy is 0 because it is not in motion?
Exactly!

I am just realizing that we have a sign error here, perhaps this was the source of your confusion.

It should be 1/2mv^2 + mgh = constant right? Sorry I did not notice this before.
Dec6-12, 06:59 PM   #19
 
thanks so much for your all your help and time!
Dec6-12, 07:03 PM   #20
 
Quote by benrocks1 View Post
While the kinetic energy increases, the potential energy will decrease. Is that correct?
ONLY for certain problems.

Consider a pendulum swinging back and forth with no air resistance or friction.

At the top of the swing:

PE = Maximum = mghmax where h is measured from the bottom of the swing
KE = Zero because it stops momentarily

At the bottom of the swing:

PE = Zero
KE = Maximium (= 0.5mV^2)

At any point in between:

PE + KE = Constant = mghmax
Dec6-12, 09:20 PM   #21
 
Went back and corrected sign error in my posts (don't want to confuse anyone coming along later).

Can't believe I can post so many times and not notice this, what I get for being half asleep I guess
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kinetic energy, potential energy
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