How to Identify a Metal Using Work Function and Wavelength?

In summary, the conversation revolves around calculating the work function of a metal by using the formula for the photoelectric effect. The specific scenario given is that of ultraviolet radiation with a wavelength of 200.0 nm hitting a metal and electrons being emitted, with a stopping potential of 3.33 V. The formula is suggested to be a simple plug and chug process, with the only potential challenge being converting between different units of energy.
  • #1
geej77
6
0
Calculating Work Function

I am having trouble identifying a metal (based on its work function) given the wavelength and stopping potential. I will give more specifics below but can anyone help me with useful formulas to make this a little more streamlined in the future? Thanks!

Ultraviolet radiation with wavelength 200.0 nm hits a metal and electrons are emitted, which can be stopped by a potential of 3.33 V. What is the work function/identity of the metal?
 
Last edited:
Chemistry news on Phys.org
  • #2
Start with the equation describing photoelectric effect. You will need to convert between different ways of expressing energy, other than that it is just a simple plug and chug.
 
  • #3
Thanks I will give it a shot!
 

1. What is the definition of work function?

The work function is the minimum amount of energy required to remove an electron from the surface of a material. It is usually measured in electron volts (eV) or joules (J).

2. How is the work function calculated?

The work function can be calculated by measuring the energy of the ejected electrons in the photoelectric effect, or by using the formula: work function = energy of incident photon - maximum kinetic energy of ejected electron.

3. What factors affect the work function?

The work function of a material can be affected by its chemical composition, crystal structure, and surface conditions. It can also be influenced by external factors such as temperature and electric fields.

4. Why is the work function important in semiconductor devices?

The work function is important in semiconductor devices because it determines the ease at which electrons can be emitted from the surface, which affects the efficiency and performance of the device. It also plays a role in determining the band gap and conductivity of the material.

5. How can the work function be used in practical applications?

The work function has many practical applications, such as in solar cells, where it is used to calculate the energy needed to remove electrons from the material and generate electricity. It is also important in the design of electron tubes, vacuum tubes, and various types of electronic devices.

Similar threads

I Question about the Photoelectric Effect and the Work Function of a Metal
    • Quantum Physics
Replies
5
Views
633
Wavelength-stopping potential dependence
    • Introductory Physics Homework Help
Replies
5
Views
1K
Calculating Stopping Potential in Photoelectric Effect Experiment
    • Introductory Physics Homework Help
Replies
4
Views
1K
How does thermionic emission work?
    • Mechanics
Replies
2
Views
2K
Calculating Kinetic Energy of Photoelectrons in Ultraviolet Metal Interaction
    • Introductory Physics Homework Help
Replies
6
Views
1K
Quantum Physics: Work Function and Electric Potential
    • Introductory Physics Homework Help
Replies
1
Views
905
Threshold Wavelength for Photoelectric Effect - 6.476103179e-19J
    • Introductory Physics Homework Help
Replies
7
Views
7K
Work function and kinetic energy
    • Introductory Physics Homework Help
Replies
1
Views
1K
Minimum wavelength of electrons ejected from metal
    • Introductory Physics Homework Help
Replies
1
Views
2K
Calculating Work Function of Metal in a Photocell
    • Introductory Physics Homework Help
Replies
2
Views
16K

Hot Threads

Recent Insights

Back
Top