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Homework Statement
A gorilla is swinging on vines. Each vine is 30 meters long and the gorilla catches each vine when it is at rest 15 degrees to the left of the (downwards) vertical, swings on it until it stops at an angle of 15 degrees to the right of vertical, and then grabs the next vine at rest and repeats the process.
What is the gorilla's average horizontal speed in m/s?
Details and assumptions
You may take g to be 9.8 m/s2.
You may treat the gorilla as a simple pendulum and use the small angle approximation.
Homework Equations
ω=[itex]\sqrt{}g/l[/itex]
T=2[itex]\pi[/itex][itex]\sqrt{}L/g[/itex]
-gsin[itex]\theta[/itex]=d[itex]^{}2[/itex]s/dt[itex]^{}2[/itex]
The Attempt at a Solution
Since the acceleration in the direction of motion is -gsin[itex]\theta[/itex]=d[itex]^{}2[/itex]s/dt[itex]^{}2[/itex], i consider taking the integral of this to find the velocity and i sweep on the bounds from -pi/12 to pi/12 radians. I can then find the average velocity. My only concern is what they mean by "horizontal velocity". Also, how can omega be used in this scenario? Any help would be appreciated.
Also, sorry for the janky fonts. I'm new to the latex option.