For the precision the problem demands E(r) and V(r).Tomsk said:are you calculating the field strength at those points? I don't see why else they'd give you the size of the charge and of the radii. Also, you need to consider the total charge inside your general sphere of radius r2, not just the charge on the metal sphere.
An electric field is a physical quantity that describes the force experienced by a charged particle in the presence of other charged particles. It is a vector quantity and is measured in units of Newtons per Coulomb (N/C).
The electric field of a spherical shell is calculated using the formula E = Q/(4πε₀r²), where Q is the total charge of the shell, ε₀ is the permittivity of free space, and r is the distance from the center of the shell to the point where the electric field is being calculated.
Electric potential is a scalar quantity that describes the amount of electric potential energy per unit charge at a given point in space. Electric field, on the other hand, is a vector quantity that describes the force experienced by a charged particle in the presence of other charged particles.
The electric potential of a spherical shell is calculated using the formula V = kQ/r, where k is the Coulomb's constant, Q is the total charge of the shell, and r is the distance from the center of the shell to the point where the electric potential is being calculated.
Inside the shell, both the electric field and potential are zero since the charges on the shell cancel each other out. Outside the shell, the electric field and potential decrease with increasing distance from the shell, following the inverse square law.