Solving Transfer of Energy: Find Height Dropped for Bowling Ball

  • Thread starter Renzokuken
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In summary, the bowling ball was dropped from a height of 107.8h meters and it would take 333.55 kJ of energy to melt 5g of ice.
  • #1
Renzokuken
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1. Homework Statement
An 11 kg bowling ball at 0 degrees C is dropped into a tub containing a mixture of ice and water. A short time later, when a new equilibrium has been established, there are 5.0 g less ice.
From what height was the ball dropped? Assume that no water or ice splashes out.




Homework Equations


PE=mgh

3. The Attempt at a Solution
PE=mgh=11*9.8*h=107.8h
I don't know what to do after this.
 
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  • #2
You should find out how much energy it would take to melt 5 g of ice.
 
  • #3
Is there a formula to find how much energy it takes for 5g of ice to melt?
 
  • #4
You need to use the enthalpy of fusion. For water it is 6.0095 kJ/mol, or 333.55 kJ/kg
 

1. How is the height dropped for a bowling ball calculated?

The height dropped for a bowling ball can be calculated using the formula h = (1/2) * g * t^2, where h is the height in meters, g is the acceleration due to gravity (9.8 m/s^2), and t is the time in seconds.

2. What factors affect the height dropped for a bowling ball?

The height dropped for a bowling ball is affected by the mass of the ball, the initial velocity at which it is dropped, and the force of gravity acting on it.

3. How does the height dropped for a bowling ball affect its energy?

The height dropped for a bowling ball is directly proportional to its potential energy. As the ball is dropped, it gains potential energy due to its position in the Earth's gravitational field.

4. Can the height dropped for a bowling ball be used to calculate its kinetic energy?

Yes, the height dropped for a bowling ball can be used to calculate its kinetic energy using the formula KE = (1/2) * m * v^2, where KE is the kinetic energy, m is the mass of the ball, and v is its velocity.

5. How does the height dropped for a bowling ball relate to its speed?

The height dropped for a bowling ball is directly proportional to its speed. As the ball falls, it gains speed due to the acceleration of gravity, and the height dropped can be used to calculate its final velocity using the formula v = g * t.

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