Magnetic field inside capacitor - is this right?

In summary, a 10 cm diameter parallel plate capacitor with a 1 mm spacing has an increasing electric field between the plates at a rate of 1.0 * 10^6 V/ms. By using the Ampere Maxwell equation, the magnetic field strength at the axis is infinite, while the magnetic field strength 3.0 cm from the axis is 3.688 e-7 T.
  • #1
bcjochim07
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Homework Statement


A 10 cm diameter parallel plate capacitor has a 1 mm spacing. The electric field between the plates is increasing at the rate of 1.0 * 10 ^6 V/ms. What is the magnetic field strength (a) on the axis (b) 3.0 cm from the axis


Homework Equations





The Attempt at a Solution


dE/dt = 1.0 e6
displacement current = dFlux/dt * permittivity constant = dE/dt * A * 8.85e-12
displacement current = 1.0e6 * pi * .05^2 * 8.85e-12 = 6.95e-8

The first part of the Ampere Maxwell equation falls out, leaving
B*s = displacement current

For on axis s= 0 , so is the magnetic field infinite?

3cm:
B*2pi*.03 = 6.95e-8 B = 3.688 e-7 T

Is this correct?
 
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  • #2
actually I messed the problem up here. I got it now.
 
Last edited:
  • #3


I would say that your calculations appear to be mostly correct. However, there are a few things that could be clarified or expanded upon.

Firstly, it would be helpful to specify the units for each variable and to use consistent units throughout the calculation. For example, the electric field should be given in units of volts per meter (V/m) and the displacement current should be given in units of amperes (A).

Additionally, it would be helpful to explain the equations used and how they relate to the problem at hand. For example, you could mention that the displacement current is related to the change in electric field over time and is a key component in the Ampere-Maxwell equation, which relates magnetic fields to electric currents.

As for your question about the magnetic field being infinite on the axis, it is important to note that the magnetic field is not truly infinite, but rather becomes very large as the distance from the axis approaches zero. This is because the displacement current, and therefore the magnetic field, is directly proportional to the electric field, which is increasing at a very high rate in this problem.

Overall, your approach and calculations seem to be on the right track, but it would be beneficial to provide more context and explanation for each step.
 

1. What is a magnetic field inside a capacitor?

The magnetic field inside a capacitor is the region of space where the lines of magnetic force are present due to the movement of charges within the capacitor. It is perpendicular to the electric field inside the capacitor and is created by the flow of current through the circuit.

2. How is the magnetic field inside a capacitor calculated?

The magnetic field inside a capacitor can be calculated using the formula B = μ0I/2πr, where B is the magnetic field, μ0 is the permeability of free space, I is the current flowing through the capacitor, and r is the distance from the center of the capacitor.

3. Is the magnetic field inside a capacitor constant?

No, the magnetic field inside a capacitor is not constant. It varies depending on the strength of the current flowing through the capacitor and the distance from the center of the capacitor. It is also affected by the capacitance and the material of the capacitor.

4. Can the magnetic field inside a capacitor be manipulated?

Yes, the magnetic field inside a capacitor can be manipulated by changing the current, capacitance, or distance from the center of the capacitor. It can also be affected by the surrounding materials and external magnetic fields.

5. What are the practical applications of the magnetic field inside a capacitor?

The magnetic field inside a capacitor has various practical applications, such as in electric motors, generators, and transformers. It is also used in electronic devices like speakers, microphones, and magnetic storage devices like hard drives. Additionally, it is used in medical imaging technologies such as MRI machines.

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