- #1
Petar Mali
- 290
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[tex]\delta(x)=\frac{d}{dx}\Theta(x)[/tex] - delta function like a first derivative of Heaviside step function
[tex]\Theta(x)=\int dx\delta(x)[/tex]
We use integral representation of delta function
[tex]\delta(x)=\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx}[/tex]
from that we get
[tex]\Theta(x)=\int dx\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx} [/tex]
And now we use one trick!
[tex]\Theta(x)=\int dx\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx}lim_{\epsilon \rightarrow 0^+}e^{\epsilon k} [/tex]
Consider now the expression without the limit
[tex]\frac{1}{2\pi}\int^{\infty}_{-\infty}dk\int dxe^{-i(k+i\epsilon)x}=\frac{i}{2\pi}\int^{\infty}_{-\infty}dk\frac{e^{-ikx}}{k+i\epsilon}[/tex]
we get that
[tex]\Theta(x)=\frac{i}{2\pi} lim_{\epsilon \rightarrow 0+}\int^{\infty}_{-\infty}dk\frac{e^{-ikx}}{k+i\epsilon}[/tex]
Using complex integration in lower half plane for [tex]x>0[/tex] and upper half plane for [tex]x<0[/tex] we get that the upper expression is correct. But why we can change the place of limit and integral? I'm not sure.
Thanks for your answer!
[tex]\Theta(x)=\int dx\delta(x)[/tex]
We use integral representation of delta function
[tex]\delta(x)=\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx}[/tex]
from that we get
[tex]\Theta(x)=\int dx\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx} [/tex]
And now we use one trick!
[tex]\Theta(x)=\int dx\frac{1}{2\pi}\int^{\infty}_{-\infty}dke^{-ikx}lim_{\epsilon \rightarrow 0^+}e^{\epsilon k} [/tex]
Consider now the expression without the limit
[tex]\frac{1}{2\pi}\int^{\infty}_{-\infty}dk\int dxe^{-i(k+i\epsilon)x}=\frac{i}{2\pi}\int^{\infty}_{-\infty}dk\frac{e^{-ikx}}{k+i\epsilon}[/tex]
we get that
[tex]\Theta(x)=\frac{i}{2\pi} lim_{\epsilon \rightarrow 0+}\int^{\infty}_{-\infty}dk\frac{e^{-ikx}}{k+i\epsilon}[/tex]
Using complex integration in lower half plane for [tex]x>0[/tex] and upper half plane for [tex]x<0[/tex] we get that the upper expression is correct. But why we can change the place of limit and integral? I'm not sure.
Thanks for your answer!