Are My Calculus Derivatives Correct?

In summary, the derivative of y with respect to x for both questions is (5x^4 e^-3x) + (x^5 -3e^-3x) .
  • #1
eeyore81
2
0
For both questions i have to find dy/dx
1. y=x^5e^-3x

I got (5x^4 e^-3x) + (x^5 (-3xe^-3x-1))

some how that doesn't look right to me. not too sure...

2.
1-e^-x
y= --------
1+e^2x
My answer was:


(e^-x) - (1-e^-x) (2xe^2x-1)
y'= -----------------------------
1+e^2x


Thanks for your help! It's much appreciated!
 
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  • #2
eeyore81 said:
For both questions i have to find dy/dx
1. y=x^5e^-3x
I got (5x^4 e^-3x) + (x^5 (-3xe^-3x-1))
some how that doesn't look right to me. not too sure...
2.
1-e^-x
y= --------
1+e^2x
My answer was: (e^-x) - (1-e^-x) (2xe^2x-1)
y'= -----------------------------
1+e^2x
Thanks for your help! It's much appreciated!

1.It's wrong.It is an "x" too much.Figure out where. :wink:
2.It's wrong.Again an "x" too much,a 'minus' missing,a whole term missing and a sqare on the denominator.Figure it out yourself.

Daniel.
 
  • #3
First of all, thanks for replying, I'm still working on fixing the 2nd question, but i think i got the first one, the answer should be:


y' = (5x^4 e^-3x) + (x^5 -3e^-3x)
 

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