- #1
quietrain
- 655
- 2
if i have a current carrying straight long wire, I = I0sin(wt)
why is gauss law ∇.E = 0?
i thought only for steady currents , then the charges reside on surface, that's why 0 charge enclosed, and hence gauss law gives 0 right?
so now since i have a time varying current, what should gauss law give?
thanks!
why is gauss law ∇.E = 0?
i thought only for steady currents , then the charges reside on surface, that's why 0 charge enclosed, and hence gauss law gives 0 right?
so now since i have a time varying current, what should gauss law give?
thanks!