Charge and voltage of capacitors?

In summary, assuming C1 = C2 = C3 = 16.0 µF and C4 = 28.5 µF, and with Q2 = 12.4 µC, the charge on each of the capacitors is Q1 = 12.4 µC, Q3 = 24.8 µC, and Q4 = 44.175 µC. The voltage across each capacitor is V1 = V2 = 0.775 V and V3 = V4 = 1.55 V. The voltage Vab across the entire combination is 1.55 V. To find Q4, use conservation of charge to relate it to the other charges.
  • #1
gmmstr827
86
1

Homework Statement



Suppose that C1 = C2 = C3 = 16.0 µF and C4 = 28.5 µF. If the charge on C2 is Q2 = 12.4 µC, determine the charge on each of the other capacitors, the voltage across each capacitor, and the voltage Vab across the entire combination.

http://i29.photobucket.com/albums/c261/gmmstr827/capacitor.jpg

Homework Equations



Q=CV

The Attempt at a Solution



C1=C2=C3=16.0 µF, C4=28.5 µF
Q2=12.4 µC

Note that V1=V2, V3=V4, and Q1=Q2

V2=Q2/C2
V2 = 12.4 µC / 16.0 µF
V1 = V2 = 0.775 V

Note that V3 = 2*V2

V3 = 2*0.775 V
V3 = 1.55 V

Q3=C3*V3
Q3 = 16.0 µF * 1.55 V
Q3 = 24.8 µC

Q4 = C4*V4
Q4 = 28.5 µF * 1.55 V
Q4 = 44.175 µC

Therefore
Q1 = Q2 = 12.4 µC
Q3 = 24.8 µC
Q4 = 44.175 µC
V1 = V2 = 0.775 V
V3 = V4 = 1.55 VIs that correct?
 
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  • #2
You were doing fine until you ran up against Q4. Take a close look at what you've written.
 
  • #3
gneill said:
You were doing fine until you ran up against Q4. Take a close look at what you've written.

Guess I didn't hit the Ctrl+C hard enough that time and pasted the previous thing. I fixed it. The numbers all work out though I believe?
 
  • #4
V3≠v4

Use conservation of charge to find how Q4 is related to the other charges.
 
  • #5


I would say that your solution appears to be correct based on the given information and equations. However, it would be helpful to include units in your calculations and final answers. Also, it would be useful to explain your reasoning and assumptions in more detail for better understanding. Overall, your response demonstrates a good understanding of the concepts of charge and voltage in capacitors.
 

1. What is the relationship between charge and voltage of capacitors?

The charge and voltage of a capacitor are directly proportional to each other. This means that as the voltage across a capacitor increases, the charge stored in it also increases. Similarly, as the voltage decreases, the charge decreases.

2. How does the charge on a capacitor affect its voltage?

The charge on a capacitor can affect its voltage by changing the amount of energy stored in the capacitor. As the charge increases, the voltage across the capacitor also increases, and vice versa.

3. Can a capacitor have a charge without a voltage?

No, a capacitor cannot have a charge without a voltage. In order for a capacitor to have a charge, it needs to have a voltage difference across its two plates. If there is no voltage, there will be no charge stored in the capacitor.

4. What happens to the voltage of a capacitor when it is connected to a battery?

When a capacitor is connected to a battery, the voltage across the capacitor increases until it reaches the same voltage as the battery. This is because the battery is a source of potential difference, and the capacitor charges until it reaches the same potential difference as the battery.

5. How does the capacitance of a capacitor affect its voltage?

The capacitance of a capacitor affects its voltage by determining how much charge can be stored in the capacitor. A higher capacitance means that the capacitor can store more charge, resulting in a higher voltage for the same amount of charge. Similarly, a lower capacitance means that the capacitor can store less charge, resulting in a lower voltage for the same amount of charge.

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