The formula for calculating ymax(x) of Two Harmonic Waves at x = 2.21m is: ymax(x) = A1sin(k1x + ω1t) + A2sin(k2x + ω2t), where A1 and A2 are the amplitudes of the two waves, k1 and k2 are the wave numbers, ω1 and ω2 are the angular frequencies, and x is the position at which the waves are being measured.
A1 and A2 represent the amplitudes of the two waves, which determine the maximum displacement of the waves from the equilibrium position. k1 and k2 represent the wave numbers, which are related to the wavelength of the waves. ω1 and ω2 represent the angular frequencies, which are related to the period of the waves. x represents the position at which the waves are being measured.
If the two waves have the same frequency and wavelength, they are in phase and will produce a larger amplitude at their peak and trough points. If the two waves have different frequencies or wavelengths, they are out of phase and will produce smaller amplitudes at their peak and trough points.
Yes, this formula can be used for any type of harmonic waves, as long as they have the same frequency and wavelength.
To find the maximum displacement of the waves, simply plug in the values for A1, A2, k1, k2, ω1, ω2, and x into the formula and solve for ymax(x). This will give you the maximum displacement of the waves at the specified position (x = 2.21m).