Solving for the Antiderivative: 2/x - 5e^5x | Math Homework Help

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In summary, an antiderivative is the inverse operation of a derivative and is found using integration techniques. The antiderivative of 2/x is ln|x| + C and the antiderivative of 5e^5x is e^5x + C. To solve for the antiderivative of 2/x - 5e^5x, use the linearity property of integration to split the function and then solve for each antiderivative separately using integration techniques.
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Homework Statement


Sorry I have class at 8 and I am getting myself confused...
What is the anti-derivative of 2/x - 5e^5x


Homework Equations





The Attempt at a Solution


So I did this...
2 * 1/x - 5e^5x
Anti-derivative:
2ln - 5e^5x
 
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  • #2
Is an Anti-Derivitive ...another word for Integration?
if 1/x =lnx ...looks like it.
[Int]2/x - [Int]5e^5x
2[int]1/x - 5[int]e^5x
2Lnx - 5[1/5e^5x]
Ans: 2Lnx -e^5x + k

Am I right?
 

Question 1: What is an antiderivative?

An antiderivative is the inverse operation of a derivative. It is a function that, when differentiated, yields the original function. It is also known as the indefinite integral.

Question 2: How do you solve for the antiderivative?

To solve for the antiderivative, you must use integration techniques such as substitution, integration by parts, or partial fractions. These techniques allow you to find an expression for the antiderivative of a given function.

Question 3: What is the antiderivative of 2/x?

The antiderivative of 2/x is ln|x| + C, where C is a constant. This can be found using the integration technique of substitution, where u = 2/x and du = -2/x^2 dx.

Question 4: What is the antiderivative of 5e^5x?

The antiderivative of 5e^5x is e^5x + C, where C is a constant. This can be found using the integration technique of substitution, where u = 5x and du = 5dx.

Question 5: How do you solve for the antiderivative of 2/x - 5e^5x?

To solve for the antiderivative of 2/x - 5e^5x, you must use the linearity property of integration to split the function into two separate antiderivatives: the antiderivative of 2/x and the antiderivative of 5e^5x. Then, use the techniques mentioned in previous questions to solve for each antiderivative separately.

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