Simple Coulomb Exec. With Pix

[Deicider]

Homework Statement

q1=q3=5uC,q2=-2uC

q2 and q3 have d distance so q2 with q1
d=0.1m
q3 and q1 have √2d

Homework Equations

|q1||q2|
F=k----------
r^2

The Attempt at a Solution

:S

 

[AEM]

Homework Statement

q1=q3=5uC,q2=-2uC

q2 and q3 have d distance so q2 with q1
d=0.1m
q3 and q1 have √2d

Homework Equations

|q1||q2|
F=k----------
r^2

The Attempt at a Solution

:S

There doesn't seem to be a picture with your post and you haven't told us what the question actually is.

 

[kerimek]

I would first like to clarify the homework statement for better understanding. It seems that the statement is describing a simple Coulomb's law problem with three point charges, q1, q2, and q3, with values of 5uC, -2uC, and 5uC respectively. The distance between q2 and q1 is given as 0.1m, while the distance between q3 and q1 is described as √2 times the distance between q2 and q1.

To solve this problem, we can use Coulomb's law equation, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as F = k(q1q2)/r^2, where k is the Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

Using this equation, we can calculate the force between q2 and q1 as F = (9x10^9)(5x10^-6)(-2x10^-6)/(0.1)^2 = -90N. Similarly, the force between q3 and q1 can be calculated as F = (9x10^9)(5x10^-6)(5x10^-6)/(√2(0.1))^2 = 398N.

It is important to note that the negative sign in the force between q2 and q1 indicates that the force is attractive, while the positive sign in the force between q3 and q1 indicates that the force is repulsive.

In conclusion, the simple Coulomb's law problem described in the homework statement can be solved by using the Coulomb's law equation and considering the directions of the forces as either attractive or repulsive.