- #1
lukeex
- 1
- 0
hey guys,
I am currently trying to implement a voltage divider to step down from 9V DC for a digital output.
I am using two resistors, 3.3M ohm & 2.7M ohm in series.
When I measure the voltage across both of them using a multimeter I get 9.5V
Across the 3.3M ohm resistor I get 2.2V and across the 2.7M ohm resistor 1.8V.
I don't have any idea where I have lost the 5V and there is no other resistances in series, it is connected straight to a 9V battery, using a breadboard.
If anyone has any suggestions at all it would be much appreciated.
Thanks
I am currently trying to implement a voltage divider to step down from 9V DC for a digital output.
I am using two resistors, 3.3M ohm & 2.7M ohm in series.
When I measure the voltage across both of them using a multimeter I get 9.5V
Across the 3.3M ohm resistor I get 2.2V and across the 2.7M ohm resistor 1.8V.
I don't have any idea where I have lost the 5V and there is no other resistances in series, it is connected straight to a 9V battery, using a breadboard.
If anyone has any suggestions at all it would be much appreciated.
Thanks