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kubombelar
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Homework Statement
calculate the escape velocity of a 10,500kg spaceship from earth. mass of Earth is 5.98*10kg and radius of the Earth is 6.38*10kg.elevant equations
2GM/R
Escape velocity is the minimum speed required for an object to break free from the gravitational pull of a celestial body, such as a planet or moon.
Escape velocity is calculated using the formula v = √(2GM/r), where v is the escape velocity, G is the gravitational constant, M is the mass of the celestial body, and r is the distance from the center of the celestial body to the object.
The factors that affect escape velocity include the mass and radius of the celestial body, as well as the distance from the center of the body to the object. The escape velocity also depends on the gravitational constant, which is a universal constant.
Escape velocity is important for space travel because it determines the minimum speed required for a spacecraft to leave the gravitational pull of a celestial body and travel into space. Without reaching escape velocity, a spacecraft would not be able to break free from the gravitational pull and travel to other planets or moons.
Yes, escape velocity can be achieved by spacecrafts through the use of powerful engines and thrusters. However, the amount of energy and fuel required to reach escape velocity depends on the mass and gravitational pull of the celestial body, making it a challenging feat to achieve.