- #1
robert25pl
- 62
- 0
Finding E and B fields from forces experinced by a test charge with three diferent velocities
F1=qEo(ax-ay+az) for v1=Uo*ax
F2=qEo(ax-ay-az) for v2=Uo*ay
F3=0 for v3=Uo*az
I used Lorenz force equation and by reduce E by subtracting equation 1 from 2 and eq. 3 from 2 I got
Uo(ay-ax) X B = Eo(-2az)
Uo(ay-az) X B = qEo(ax-ay-az)
So
B = C(-2az) X (ax-ay-az) = -C
Then I solved For C and for B. I not sure that I got right to this point. Can someone help me with that problem. Thanks
F1=qEo(ax-ay+az) for v1=Uo*ax
F2=qEo(ax-ay-az) for v2=Uo*ay
F3=0 for v3=Uo*az
I used Lorenz force equation and by reduce E by subtracting equation 1 from 2 and eq. 3 from 2 I got
Uo(ay-ax) X B = Eo(-2az)
Uo(ay-az) X B = qEo(ax-ay-az)
So
B = C(-2az) X (ax-ay-az) = -C
Then I solved For C and for B. I not sure that I got right to this point. Can someone help me with that problem. Thanks