How does pressure and volume affect the work done by gas in a vacuum?

In summary, 1-When gas expands in a vacuum, work done is zero.2-Pressure is caused by force, and in a vacuum there is no force, so pressure is zero.3-I proved that pressure is zero in the situation you described.4-There is no need to, we have a satisfactory explanation! thanks for that explanation
  • #1
nil1996
301
7
I learned that work done by gas is zero when a gas expands in vacuum.
But the volume and pressure of the gas change.Then how work done by gas is zero?
 
Physics news on Phys.org
  • #2
The point is,in a vacuum,there is nothing that the gas can do work on!
Also,there is nothing that the gas has to overcome its pressure to expand,so the work it does in expanding is zero.
For another thing,pressure of a gas is the force that its particles exert on the walls of their container divided by the area.But in a vacuum there is no container,so the pressure is zero.
For another reasoning leading to pressure being zero.In a vacuum,whatever the temperature of the gas is,its higher than the temperature of the environment,so it radiates energy until its temperature reaches 0K(classically). And using [itex] PV=nRT [/itex],we will have [itex] PV=0 [/itex]. But the volume of the gas can't be zero,so P=0. Using the ideal gas equation is justified because in a vacuum,the only force on the particles is the force by other ones. There is also diffusion to the directions leading to outside of the gas because the concentration decreases in those directions and I think the diffusion flux is dominant so the gas expands and it will behave like an ideal gas with a very good approximation.
 
  • #3
Why can't we say that in vacuum some negative pressure is doing work on the gas?
 
  • #4
nil1996 said:
Why can't we say that in vacuum some negative pressure is doing work on the gas?

1-Its not well-defined,maybe not defined at all!
2-Pressure is casued by force.If we consider the gas as one entity,then there is only one thing in our system,the gas.So there can be no force,and so,no pressure.
3-I just proved that the pressure of the gas is zero in the situation you described.
4-There is no need to,we have a satisfactory explanation!
 
  • #5
thanks for that explanation
 
  • #6
nil1996 said:
I learned that work done by gas is zero when a gas expands in vacuum.
But the volume and pressure of the gas change.Then how work done by gas is zero?


Pressure decreases, but we have a bigger tank of gas.

(for example when a small gas tank explodes inside a large vacuum tank)

5 liters of gas in 10 atm has as much pneumatic energy as 10 liters of gas in 5 atm
 

1. What is "work done by gas in vacuum"?

"Work done by gas in vacuum" refers to the amount of work performed by a gas as it expands or contracts in a vacuum. This work is done against the surrounding pressure and results in a change in the volume of the gas.

2. Why is it important to study the work done by gas in vacuum?

Understanding the work done by gas in vacuum is important in various fields such as thermodynamics, physics, and engineering. It helps us analyze and predict the behavior of gases in different environments and can also be used to design efficient engines and other mechanical devices.

3. How is work done by gas in vacuum calculated?

The work done by gas in vacuum can be calculated using the formula W = PΔV, where W is the work done, P is the surrounding pressure, and ΔV is the change in volume of the gas.

4. What factors affect the work done by gas in vacuum?

The work done by gas in vacuum is affected by several factors, including the pressure of the surrounding environment, the initial and final volumes of the gas, and the type of gas being used. Other factors such as temperature and the presence of other gases can also impact the work done.

5. Can the work done by gas in vacuum be negative?

Yes, the work done by gas in vacuum can be negative if the gas is compressed and its volume decreases. In this case, the work is done by the gas on the surrounding environment rather than the other way around. This can happen, for example, when a piston compresses a gas in an engine.

Similar threads

Replies
15
Views
2K
Replies
8
Views
1K
Replies
2
Views
15K
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
13
Views
762
  • Thermodynamics
Replies
8
Views
512
Replies
1
Views
14K
  • Mechanics
Replies
9
Views
2K
Replies
56
Views
3K
Replies
1
Views
5K
Back
Top