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DaOneEnOnly
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Homework Statement
Have to answer all of the following...
A. By titration, 15.0mL of 0.1008M Sodium hydroxide is needed to neutralize a 0.2053g sample of an organic acid. What is the molar mass of the acid if it is monoprotic?
B.An elemental analysis of the acid indicates that it is composed of 5.89% H, 70.6%C, and 23.5% O by mass. what is its molecular formula.
Homework Equations
(N)(M)(V)=(N)(M)(V) possibly
n-moles
m-molarity
v-volume.
Molecular Formula= [tex]Molecular weight/Emprical Formula Weight[/tex]
The Attempt at a Solution
ok I orginally wanted to go like this for part A.
.2053g x [tex]1mol/(the molar mass of the acid which I don't have)[/tex] x [tex](moles of the acid)/(moles of NaOH)[/tex] x [tex]0.1008mol NaOH/1L[/tex]
but I realized very early on that it wouldn't work. So I tried...
.015L NaOH x [tex]0.1008mol NaOH/1L NaOH[/tex] x (mol to mol ratio...)
but I once again don't have that information.. since I can't write a chemical equation b/c I don't know the organic acid.
Need a direction...
For B.
I found the EF
5.89g H x [tex]1mol H/1.008g H[/tex]= 5.84mol H
70.6g C x [tex]1mol C/12g C[/tex]=5.8833mol C
23.5g O x [tex]1mol O/16g O[/tex]=1.468mol O
then divide by O
5.84mol H/1.468= 4 H
5.88mol C/1.468= 4 C
1.46mol H/1.468= 1 O
EF= [tex]C{4}[/tex][tex]H{4}[/tex]O
But I don't have the molecular weight to calculate the answer of the the Molecular formula. Do I?
I realize that if I get the MF I should be able to make a Chemical equation... Can I do that with the EF though? I'm not sure that is "legal". Nor do I know what the products would be.
[tex]C{4}[/tex][tex]H{4}[/tex]O + NaOH --> ? + HOH?