Does this mean there is a detector that is sensitive to a 0.05 nm-wide band at wavelength 325 nm?Carrie003 said:Homework Statement
I am given a plasma at 8000 Kelvin and assume its an ideal blackbody. I have slit of 0.01 cm^2, observing at wavelength 325 nm with a spectral bandwidth of 0.05 nm.
I don't understand this statement. Could you please quote the problem question exactly, word-for-word?The problem asks that the actually continuum under these conditions is 1 pW.
Of what? The detector?What is the emissivity?
Homework Equations
Planck's curve
The Attempt at a Solution
I do not know how to treat a continuum when before I was looking at a particular bandwidth.
Emissivity is the measure of an object's ability to emit thermal radiation. It is usually represented by the Greek letter epsilon (ε) and is given as a value between 0 and 1, with 1 being a perfect emitter.
Emissivity is dependent on both temperature and wavelength. As temperature increases, so does the emissivity of an object. Additionally, emissivity can vary at different wavelengths, with some materials being more emissive at certain wavelengths than others.
The emissivity problem at 8000K plasma at 325nm refers to the challenge of accurately measuring the emissivity of a high-temperature plasma at a specific wavelength. This is important in fields such as materials science and astrophysics, where plasma is a common occurrence.
The emissivity problem at 8000K plasma at 325nm is typically addressed through experimental methods such as spectroscopy. This involves measuring the intensity of radiation emitted by the plasma at different wavelengths and using mathematical models to determine the emissivity at the desired wavelength.
Understanding emissivity is important in many scientific and industrial fields, as it affects the heat transfer and energy balance of objects. It is also crucial in the design and development of technologies that involve high temperatures, such as engines and power plants.