QM 1st order perturbation theory

J=3/2, S=3/2, and L=0. Plugging these values into the formula, we get:g = 1 + \frac{3/2(3/2+1) - 3/2(3/2+1) + 0(0+1)}{2(3/2)(3/2+1)} = 3/2This means that the Landé g-factor for this state is 3/2. Using this formula, you can calculate the g-factor for each of the four spin states and then plug them into the equation for ΔB.In summary, to determine the value of the DC magnetic field for the absorption of
  • #1
quantumdude10
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Homework Statement


Material contains [tex]10^{19}[/tex]/[tex]cm^{3}[/tex] [tex]Cr^{3\frac{1}{2}}[/tex].
in the state [tex]\Psi[/tex](l=0, s = 3/2) with fourfold degenerate ground states. When a DC magnetic Field in x-direction is applied to the material, the spin degeneracy is lifted. At near Zero absolute temperature, only ground states are occupied.

The Question:

Determine the Value of the DC magnetic field if the resultant Zeeman level seperations will result in the absorption of a 10GHz signal propagating in the material


Homework Equations



Probably Angular momentum wavefunctions and equations, Spin Matrices


The Attempt at a Solution



Given that the Material is at Near Zero absolute temperature, I think the Wavefunctions that we have to worry about are for the following spins:

[itex]
\left|\frac{3}{2},\frac{3}{2}\right\rangle, \left|\frac{3}{2},\frac{1}{2}\right\rangle \left|\frac{3}{2},-\frac{1}{2}\right\rangle \left|\frac{3}{2},-\frac{3}{2}\right\rangle
[/itex]
For this DC field, I think we have to apply first order perturbation theory in the following:

Perturbation Hamiltonian : hbar*g*([tex]\frac{e}{2m}[/tex])L.B

Any ideas if this is right or wrong?

Thanks
 
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in advance for any help!

Thank you for your post. Your approach to the problem seems reasonable. To determine the value of the DC magnetic field, we can use the following equation:

ΔE = gμBΔB

Where:
ΔE = the energy difference between two spin states
g = the Landé g-factor
μB = the Bohr magneton
ΔB = the change in magnetic field

In this case, we are given that the material contains 10^19/cm^3 Cr^(3/2) in the state Ψ(l=0, s=3/2), which has a fourfold degenerate ground state. At near zero absolute temperature, only the ground states are occupied. This means that we only need to consider the four spin states you mentioned in your attempt at a solution.

To determine the energy difference between these states, we can use the following equation:

ΔE = E_β - E_α = gβμBΔB - gαμBΔB = (gβ - gα)μBΔB

Where:
E_β = the energy of state β
E_α = the energy of state α
gβ = the Landé g-factor of state β
gα = the Landé g-factor of state α
μB = the Bohr magneton
ΔB = the change in magnetic field

Since we are interested in the absorption of a 10GHz signal, we can set the energy difference equal to hν, where h is Planck's constant and ν is the frequency of the signal. This gives us the following equation:

hν = (gβ - gα)μBΔB

Solving for ΔB, we get:

ΔB = hν/((gβ - gα)μB)

Now, we need to determine the Landé g-factors for the four spin states. This can be done using spin matrices. The g-factor for a spin state can be calculated using the following formula:

g = 1 + \frac{J(J+1) - S(S+1) + L(L+1)}{2J(J+1)}

Where:
J = total angular momentum quantum number
S = spin quantum number
L = orbital angular momentum quantum number

For the spin state Ψ(l=0, s=3/
 

1. What is QM 1st order perturbation theory?

QM 1st order perturbation theory is a mathematical approach used to calculate the changes in the energy levels of a quantum system when it is subjected to a small perturbation, or disturbance, from its original state. It is often used to study the effects of external fields, such as electric or magnetic fields, on quantum systems.

2. How is QM 1st order perturbation theory applied?

In QM 1st order perturbation theory, the perturbed energy levels are calculated by adding the unperturbed energy levels of the system with the first-order correction term, which is proportional to the strength of the perturbation. The perturbation theory equations are then solved iteratively to find the energy levels to a desired level of accuracy.

3. What are the assumptions of QM 1st order perturbation theory?

QM 1st order perturbation theory assumes that the perturbation is small enough to not cause significant changes in the system, and that the system is initially in an eigenstate of the unperturbed Hamiltonian. It also assumes that the perturbation is time-independent, and that the perturbation is not degenerate with the unperturbed system.

4. What are the limitations of QM 1st order perturbation theory?

QM 1st order perturbation theory is only accurate for small perturbations, as the higher-order corrections become increasingly significant for larger perturbations. It also does not work for degenerate systems, and can only be applied to systems with discrete energy levels.

5. How does QM 1st order perturbation theory relate to other perturbation methods?

QM 1st order perturbation theory is the simplest form of perturbation theory, and is often used as a starting point for more complex perturbation methods. It can also be extended to higher orders of perturbation, such as 2nd or 3rd order, to improve the accuracy of the calculations.

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