Different Clock Rates Throughout Accelerating Spaceship

jartsa

Well you just have to add one small thing to the clocks in a rocket scenario:

The extra velocity of a clock at the rear of an accelerating rocket is not enough to explain the time differences observed inside the rocket.

But if we add the extra velocity of a clock that is carried from the rear to the nose, then the final time difference between that clock and a clock at the nose is fully explained by the velocity time dilation.

nitsuj

I don't get the ceiling fan, Can I not trust that if I install a fan on my spaceship and go near c, that the fan will still hold it's geometry.

You seem to be telling me that physics isn't the same in all FoRs.

1977ub

Here I refer only to the view from the "rest frame" - another inertial frame.

Just as the ladder shrinks, all kinds of other weird things happen - for me in the rest frame.

nitsuj

Ah I see, yea lots of weired things would happen for sure. However I cannot imagine all the invariants/equivalents and "see the fan" has wobble. I would think after accounting for all physical effects when transforming coordinates that the exact same geometry is calculated/found, and in turn the fan isn't wobbling, yet still perfectly balanced.

How I don't know, maybe via kinetic energy/mass the shorter blades still have the same mass as those perpendicular to motion.

1977ub

One of the simplest implications of "c is the same for all observers" is that clocks which people on the train view as synchronized / simultaneous read different time as viewed in another frame. Imagine they have a ceiling fan with the blades lining up with the direction of motion "at a particular time". Just like in barn door example, those "same times" train-wise turn out to be different time rest-frame-wise. So the opposite ceiling fan blades will line up with the train's length dimension "At different times" rest-frame-wise and thus at any particular time rest-frame-wise the moving blades are generally not going to be opposite. This all derives from ladder/barn.

1977ub

Imagine a sphere which regularly and continuously stretches to twice its size and back again. If moving high % of c seen in RF, then the leading and trailing edge are noticed no longer to be puffing out in synchrony. In fact, if speed is just right, leading/trailing ends are "out of phase" so that as trailing edge is receding toward the middle, front edge is puffing out and vice versa. The length in the direction of travel could be nearly constant over time.

SteveDave

I know this is an older topic by now but if I were to accelerate myself (no ship of any kind) to [I]c and i were holding a timepiece would it no then just be constantly stopped until I slowed back down? Also, would it then want to "catch up" to my postion relative to the surrounding Universe?

Again, I know it's an old topic but seems to me Time is only relevant to our position near the Earth as our time has only ever been measured in relation to ourselves. Just looking for some clairvoyance i suppose.

SteveDave

Also, this Barn/Ladder theory (after some research) makes sense but again imposes that all things are affected by the spacetime continuum and we know that is not true any longer thanks to the Hadron Collider setup. Please correct me if I am wrong.

my_wan

No, the timepiece you are holding will always go at a normal rate. This is because time slows for you, your body, thoughts, everything. So if time did stop for you then you would be stopped to so you will not notice.