Kicking a Ball onto a Roof

  • Thread starter DatAshe
  • Start date
  • Tags
    Ball
In summary, the problem involves a ball being launched from a point 24.0 m from the base of a 6.00 m high wall at an angle of 53.0° above the horizontal. The ball takes 2.20 seconds to reach a point vertically above the wall. By considering the horizontal references, the initial velocity of the ball can be calculated using trigonometric functions and the given angle. The resulting velocity and its x and y components form a right triangle, which can be solved to find the initial velocity of the ball.
  • #1
DatAshe
9
0

Homework Statement



A playground is on the flat roof of a city school, 4.9 m above the street below (see figure). The vertical wall of the building is h = 6.00 m high, forming a 1.1-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of θ = 53.0°; above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall.

(a) Find the speed at which the ball was launched. (Give your answer to two decimal places to reduce rounding errors in later parts.)
_______m/s

(b) Find the vertical distance by which the ball clears the wall.
________ m

(c) Find the horizontal distance from the wall to the point on the roof where the ball lands.
_________m

Homework Equations



Δx=v_x*t, v_y=v_oy+a_y*t, v_y^2=v_oy^2+2a_y*Δy, Δy=1/2(v_oy+v_y)t, Δy=v_oy*t+1/2a_yt^2

The Attempt at a Solution


So, pretty much, I tried setting the wall as the high point and then ran from there to find the other parts, but none of the numbers I'm getting work as answer or work together. I'm sorry for my sad attempt at it, but I have no clue what I am doing on this one, its completely different from anything we've done yet and I'm really confused. Any and all help is appriciated :)
 
Physics news on Phys.org
  • #2
Great problem. I did that once with a soccer ball at the start of gym class. Coming outside, I kicked it backwards over my head and onto the roof. No soccer that day as it was the only ball we had.

Try drawing a picture of the problem. Also show your work, sometimes in trying to explain it the solution becomes apparent.
 
Last edited:
  • #3
I've drawn the picture and solved it 4 or 5 times, but I keep getting the wrong answer.
 
  • #4
Show your workings and we will try to figure where it goes wrong.
Writting out all those kinematic formulae is ok but using where appropriate is the most important.

Add:
Δx=v_x*t, v_y=v_oy+a_y*t, v_y^2=v_oy^2+2a_y*Δy, Δy=1/2(v_oy+v_y)t, Δy=v_oy*t+1/2a_yt^2

You can click icon above for superscript and subscript
vx or v2
 
Last edited:
  • #5
DatAshe said:

Homework Statement



A playground is on the flat roof of a city school, 4.9 m above the street below (see figure). The vertical wall of the building is h = 6.00 m high, forming a 1.1-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of θ = 53.0°; above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall.

(a) Find the speed at which the ball was launched. (Give your answer to two decimal places to reduce rounding errors in later parts.)
_______m/s

(b) Find the vertical distance by which the ball clears the wall.
________ m

(c) Find the horizontal distance from the wall to the point on the roof where the ball lands.
_________m

Homework Equations



Δx=v_x*t, v_y=v_oy+a_y*t, v_y^2=v_oy^2+2a_y*Δy, Δy=1/2(v_oy+v_y)t, Δy=v_oy*t+1/2a_yt^2

The Attempt at a Solution


So, pretty much, I tried setting the wall as the high point and then ran from there to find the other parts, but none of the numbers I'm getting work as answer or work together. I'm sorry for my sad attempt at it, but I have no clue what I am doing on this one, its completely different from anything we've done yet and I'm really confused. Any and all help is appriciated :)

The key information is the horizontal references.
The ball began 24m from the wall, and 2.2 seconds later it was vertically above the wall.
That enables you to calculate the horizontal component of the initial velocity. The 53 degree angle [possibly a reference to a 3-4-5 triangle], enables you to get the vertical component then away you go.
 
  • #6
Hey, i have the same question to answer. To find the initial velocity of the ball do we only consider the horizontal velocity or must we also find the vertical velocity? If so, how do we find it ?
 
  • #7
hkor said:
Hey, i have the same question to answer. To find the initial velocity of the ball do we only consider the horizontal velocity or must we also find the vertical velocity? If so, how do we find it ?

Because the ball is launched at 53 degrees, if you are given/calculate the horizontal or the Vertical or the actual speed of the ball you can use that angle to calculate any of the others.

ie 53 degrees is the angle in a 3-4-5 pythagorean triangle (approx) so if the horizontal speed is 3m/s, the vertical speed is 4 m/s and the actual speed is 5 m/s.
 
  • #8
I know this thread is a little old, but I have the same exact question.

I can get you started on the problem, I found it a bit difficult at first as well. Remember that the resultant (overall velocity) and its X component and Y component form a right triangle. You are given the angle and you can solve for the X component of the velocity triangle.
 
  • #9
i kiked a bal and it go on da rof and i tol da teecher m9 get mai bal m9 or u iz foneμμμμμμμμμμμμμμμμμμμμμμμμμ
 

Attachments

  • upload_2015-4-13_14-58-8.png
    upload_2015-4-13_14-58-8.png
    45.4 KB · Views: 697

1. How high should I kick the ball to get it onto the roof?

The height of the kick needed to get the ball onto the roof will depend on the height of the roof and the distance from where you are kicking. You will need to calculate the trajectory of the ball and adjust your kick accordingly.

2. What angle should I kick the ball at to get it onto the roof?

The angle of the kick will also play a role in getting the ball onto the roof. It is generally recommended to kick the ball at a 45-degree angle, as this will provide the best balance of distance and height.

3. How much force should I use when kicking the ball onto the roof?

The amount of force needed will depend on the weight and size of the ball, as well as the height and distance of the roof. It is important to use enough force to get the ball high and far enough, but not too much that it goes over the roof.

4. What is the best type of ball to use for kicking onto a roof?

The best type of ball to use for kicking onto a roof is one that is lightweight, has good bounce, and is easy to control. A soccer ball or a rubber playground ball would be good options.

5. Is it safe to kick a ball onto a roof?

Kicking a ball onto a roof can be dangerous if proper precautions are not taken. Make sure to have a clear and safe area to kick from, and always be aware of your surroundings. It is also important to not use too much force and to wear appropriate shoes to prevent slips or falls.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
31
Views
3K
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
715
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
9K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
2K
Back
Top