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Psi-String
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Photon's energy [tex] E=\frac{hc}{\lambda} [/tex]
and photon's momentum [tex] p =\frac{E}{c} = \frac{h}{\lambda} [/tex]
The textbook say electron's momentum is [tex] p=\frac{h}{\lambda} [/tex]
I wonder that can the electron's energy be calculated by
[tex] E=\frac{hc}{\lambda} [/tex] ?
If it can, what kinds of energy does E involve? It's not only kinetic energy.
But it's interesting that when the electron has a high kinetic energy, say, 1 GeV, I can calculate it's wavelength by
[tex] \lambda = \frac{hc}{K} [/tex]
though the answer is very very very little different from that calculated by another way:
By [tex] (pc)^2 = K^2 + 2Kmc^2 [/tex] we know [tex]p[/tex]
then substitude this p into [tex] \lambda =\frac{h}{p} [/tex]
What reason cause this difference?
And when the electron's kinetic energy is low, say, 1eV, I got his wavelength by:
[tex] p= \sqrt{2mK} [/tex] and substitude this p into [tex] \lambda =\frac{h}{p} [/tex]
which answer is very different from the answer calculated by[tex] \lambda = \frac{hc}{K} [/tex] Why?? Is it because when electron has very fast speed, kinetic energy takes most of the part of its total enertgy?
(It's a big mess, if someone can't understand what I'm trying to express, please tell me)
Thanks in advance
and photon's momentum [tex] p =\frac{E}{c} = \frac{h}{\lambda} [/tex]
The textbook say electron's momentum is [tex] p=\frac{h}{\lambda} [/tex]
I wonder that can the electron's energy be calculated by
[tex] E=\frac{hc}{\lambda} [/tex] ?
If it can, what kinds of energy does E involve? It's not only kinetic energy.
But it's interesting that when the electron has a high kinetic energy, say, 1 GeV, I can calculate it's wavelength by
[tex] \lambda = \frac{hc}{K} [/tex]
though the answer is very very very little different from that calculated by another way:
By [tex] (pc)^2 = K^2 + 2Kmc^2 [/tex] we know [tex]p[/tex]
then substitude this p into [tex] \lambda =\frac{h}{p} [/tex]
What reason cause this difference?
And when the electron's kinetic energy is low, say, 1eV, I got his wavelength by:
[tex] p= \sqrt{2mK} [/tex] and substitude this p into [tex] \lambda =\frac{h}{p} [/tex]
which answer is very different from the answer calculated by[tex] \lambda = \frac{hc}{K} [/tex] Why?? Is it because when electron has very fast speed, kinetic energy takes most of the part of its total enertgy?
(It's a big mess, if someone can't understand what I'm trying to express, please tell me)
Thanks in advance
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