| New Reply |
Crude Fourier Series approximation for PDEs. |
Share Thread |
| Dec17-12, 01:43 PM | #1 |
|
|
Crude Fourier Series approximation for PDEs.
Is there a way to "crudely" approximate PDEs with Fourier series?
By saying crudely, I meant this way: Assuming I want a crude value for a differential equation using Taylor series; y' = x + y, y(0) = 1 i'd take a = 0 (since initially x = 0), y(a) = 1, y'(x) = x + y; y'(a) = 0 + 1 = 1 y"(x) = 1 + y'; y"(a) = 1 + 1 = 2 y'"(x) = 0 + y"(x); y"'(a) = 0 + 2 = 2 then y ~ 1 + x + 2/2! x^2 + 2/3! x^3. Or something similar to that. Does this crude method have an analog to Fourier-PDE solutions? |
| Dec17-12, 08:01 PM | #2 |
|
|
Hey maistral.
With a fourier series, you need to project your function to the fourier space to get the co-effecients. So the question is, how do you get an appropriate function to project to the trig basis if it's not explicit (i.e. you don't have f(x) but a DE system that describes it)? |
| New Reply |
Similar discussions for: Crude Fourier Series approximation for PDEs.
|
||||
| Thread | Forum | Replies | ||
| Solving PDEs using Fouries Series ??? | Differential Equations | 12 | ||
| PDEs and Fourier transforms - is this problem too difficult? | Differential Equations | 3 | ||
| a question on orthogonality relating to fourier analysis and also solutions of PDES | Calculus & Beyond Homework | 1 | ||
| Complex Fourier Series & Full Fourier Series | Calculus & Beyond Homework | 5 | ||
| finite approximation of PDEs | Calculus & Beyond Homework | 0 | ||