How to Calculate Work Transfer in Steady Flow Conditions

In summary, Chris is looking for help with a question involving steam under steady flow conditions. He provides initial and final state conditions and is given a formula to use. He is unsure of the variables in the formula and asks for clarification.
  • #1
niles_uk
4
0
Hi, first post so here goes:
I'm having a little trouble with a question on my tutorial, and I am not sure what to do. Here it is:
Steam under steady flow conditions has the following states:

Initial Conditions:
Pressure - 47 Bar
Spec Volume - 0.09957 m^3 / kg
Internal energy - 3420 kJ/kg
Velocity - 21 m/s

Final Conditions:
Pressure - 10 Bar
Spec Volume - 0.1636 m^3 /kg
Internal Energy - 2440 kJ/kg
Velocity - 38 m/s

Heat is added to the surroundings at the rate of 0.75 kJ/s, if the rate of steam flow is 0.36kg/s calculate the rate of work transfer

I have been given the formula:

(C1^2 /2) + u1 +p1v1 + q =(C2^2 /2) +u2 +p2v2 + w


thanks for any help in advance,
chris
 
Physics news on Phys.org
  • #2
im guessing the
u is internal energy,
v is velocity
p is pressure (in N/m)
c is specific volume?

right/wrong?
 
  • #3
****bump****
 
  • #4
??
 

What is the Steady Flow Energy Equation?

The Steady Flow Energy Equation is a fundamental equation in thermodynamics that describes the conservation of energy in a system undergoing a steady flow process. It is used to determine the energy balance of a fluid as it moves through a system, taking into account changes in potential and kinetic energy, heat transfer, and work.

How is the Steady Flow Energy Equation derived?

The Steady Flow Energy Equation is derived from the First Law of Thermodynamics, which states that energy cannot be created or destroyed, only converted from one form to another. By applying this law to a steady flow process, we can create an energy balance equation that takes into account all forms of energy in the system.

What are the assumptions made in the Steady Flow Energy Equation?

The Steady Flow Energy Equation makes several assumptions, including that the system is in steady state (meaning the properties of the fluid do not change with time), there is no work or heat transfer across the system boundaries, and there are no internal sources or sinks of energy. These assumptions allow for a simplified energy balance equation to be used.

What are the units of the Steady Flow Energy Equation?

The units of the Steady Flow Energy Equation depend on the units used for each term in the equation. Typically, energy is measured in Joules (J), mass is measured in kilograms (kg), velocity is measured in meters per second (m/s), and specific enthalpy is measured in Joules per kilogram (J/kg). However, other unit systems may be used depending on the application.

How is the Steady Flow Energy Equation applied in real-world situations?

The Steady Flow Energy Equation is used in a variety of engineering and scientific fields, including thermodynamics, fluid mechanics, and heat transfer. It is commonly used in the design and analysis of systems such as steam turbines, gas pipelines, and heat exchangers. It can also be used to analyze and improve the energy efficiency of processes and systems.

Similar threads

  • Introductory Physics Homework Help
Replies
11
Views
3K
  • Introductory Physics Homework Help
Replies
24
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
2K
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
2K
Replies
4
Views
753
Back
Top