Buoyancy of Spheres: max mass added without sinking

In summary, the maximum mass that can hang from a 40-cm-diameter Styrofoam sphere in water without sinking is approximately 2345 kg. This is determined by using the formula FB=poVog and considering the volume of the mass to be negligible compared to that of the sphere. However, this amount of mass seems unrealistically large for a Styrofoam sphere to sink in water. It is suggested to check the volume of the sphere to ensure the accuracy of the calculation.
  • #1
BennyQuixote
1
0

Homework Statement



Styrofoam has a density of 300 kg/m3. What is the maximum mass that can hang without sinking from a 40-cm-diameter Styrofoam sphere in water? Assume the volume of the mass is negligible compared to that of the sphere.

Homework Equations



FB=poVog
Volume of sphere: 4/3 π r3
p=m/V

The Attempt at a Solution



I tried this:
mo/3.35 m3=300 kg/m3
Therefore,
mo=1005 kg

So,
To find the exact amount of mass added to the Styrofoam sphere to sink in water:
1005k + m2/3.35 m3=1000 kg/m3

Therefore:
m2=2345 kg

This is obviously an obscenely large mass to make Styrofoam sink in water. Any help is appreciated.


Quixote
 
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  • #2
Check the volume of the sphere.
 
  • #3
's Answer:

Based on the given information and equations, it seems like your attempt at a solution is correct. However, the resulting mass of 2345 kg does seem quite large and unrealistic. This could be due to various factors such as the assumption that the volume of the added mass is negligible compared to the sphere, or the use of idealized equations that do not fully account for real-world conditions.

In reality, the maximum mass that can be added to a Styrofoam sphere before it sinks in water would depend on various factors such as the shape and density of the added mass, the shape and size of the Styrofoam sphere, and the properties of the water (e.g. temperature, salinity, etc.). It may also be affected by external factors such as surface tension and air pockets on the surface of the sphere.

To accurately determine the maximum mass that can be added to a Styrofoam sphere without sinking, it would be necessary to conduct experiments and account for all the relevant variables. Additionally, it is important to note that buoyancy is not the only factor that determines whether an object sinks or floats in water. Other forces such as gravity and drag also play a role and may need to be considered in a more comprehensive analysis.

In summary, while your attempt at a solution is valid based on the given information and equations, it may not accurately reflect real-world conditions. To obtain a more accurate and realistic answer, it would be necessary to conduct experiments and account for all relevant variables.
 

1. What is buoyancy?

Buoyancy is the upward force exerted by a fluid on an object that is partially or fully submerged in it. It is a result of the difference in pressure between the top and bottom of the object.

2. How is buoyancy related to the mass of a sphere?

The buoyancy of a sphere is directly proportional to the volume of the sphere and the density of the fluid it is submerged in. The more mass a sphere has, the more it will sink in a fluid with a lower density.

3. How can the maximum mass that can be added to a sphere without sinking be calculated?

The maximum mass that can be added to a sphere without sinking can be calculated using the principle of buoyancy. This involves calculating the weight of the displaced fluid and comparing it to the weight of the added mass. If the weight of the added mass is greater than the weight of the displaced fluid, the sphere will sink.

4. What factors affect the buoyancy of a sphere?

The buoyancy of a sphere is affected by its volume, the density of the fluid it is submerged in, and the gravitational force acting on it. The shape and material of the sphere can also play a role in its buoyancy.

5. How does the buoyancy of a sphere change with depth in a fluid?

The buoyancy of a sphere remains constant as long as it is completely submerged in a fluid. However, as the sphere approaches the surface of the fluid, the buoyancy decreases due to the decrease in pressure. Similarly, as the sphere sinks deeper into the fluid, the buoyancy increases due to the increase in pressure.

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