Solve Entropy & Enthalpy for Calcium Carbonate Decomposition

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In summary, to calculate delta H and delta S for the decomposition of calcium carbonate, you can use the Hf values for CaCO3, CaO, and CO2 at 25°C and 1 atm. Then, use the formula H(reaction) = SUM(r*Hf) and a similar one for entropy to find the overall delta H and delta S values. Once you have these, you can use G = H - TS to calculate delta G and verify your answer using the values in the table provided. Make sure to keep your units consistent.
  • #1
jpd5184
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Homework Statement



consider the decomposition of calcium carbonate: CaCO3(s) yields CaO(s) + CO2(g)

a) calculate delta H and delta S from standard thermodynamic data.
b) calculate delta G at 25.0C

Homework Equations



G = H - TS


The Attempt at a Solution



i added up all the thermodynamic data and got -2236 KJ/mol
now this is the delta G but for (a) I am not given a temperature(is it 25C) and i have to solve for two variables. not sure what to do.
 
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  • #2
anybody please, can u at least get me started.
 
  • #3
1. list Hf values for CaCO3, CaO, CO2 (-1207,-635,-394 kJ/mole) (this is at 25C, 1 atm)
2. H(reaction)=SUM(r*Hf), where r= reaction-coefficient= negative for reactants)
3. similar for entropy.
4. use G=H-TS for the calculation of G(reaction)
 
  • #4
Delta H and Delta S Values:
http://chemtables.tk/
(click Entropy and Enthalpy Tab)

Use Products - Reactants with the values on the website above to determine the overall delta H and delta S.

(Values for Products) - (Values for Reactants)

Then, once you have delta S and delta H, you can use the formula you provided above to find delta G.

You can also verify that your delta G is correct by using the values in the chart to see if you come out with the same answer. Make sure that you keep your values consistent! Entropy is often in J/mol while the others are in kJ/mol.
 
  • #5


For (a), you can use the standard enthalpy of formation and standard entropy values for each component, along with the stoichiometric coefficients, to calculate delta H and delta S. For example, for CaCO3, you would use the standard enthalpy of formation of -1206.9 kJ/mol and the standard entropy of 91.0 J/mol*K. You can find these values in a thermodynamic data table or online. Once you have calculated delta H and delta S for each component, you can use the equation delta G = delta H - T*delta S to solve for delta G at a given temperature (in this case, 25.0C or 298 K).
 

1. What is entropy and enthalpy?

Entropy is a measure of the disorder or randomness in a system, while enthalpy is a measure of the total energy of a system. In the context of calcium carbonate decomposition, entropy and enthalpy are used to describe the changes in energy and disorder during the reaction.

2. How do you solve for entropy and enthalpy in a reaction?

To solve for entropy and enthalpy in a reaction, you need to know the initial and final states of the system, as well as the temperature and pressure at which the reaction takes place. You can then use equations such as the Gibbs free energy equation to calculate the values of entropy and enthalpy.

3. What is the significance of solving for entropy and enthalpy in calcium carbonate decomposition?

The calculation of entropy and enthalpy in calcium carbonate decomposition allows us to understand the thermodynamics of the reaction. It helps us determine whether the reaction is spontaneous or non-spontaneous, as well as the amount of energy released or absorbed during the reaction.

4. Can entropy and enthalpy be negative?

Yes, entropy and enthalpy can be negative. A negative value for entropy indicates a decrease in disorder or randomness in the system, while a negative value for enthalpy indicates an exothermic reaction, where energy is released. In the case of calcium carbonate decomposition, both entropy and enthalpy are negative, indicating a decrease in disorder and a release of energy.

5. How do entropy and enthalpy affect the rate of calcium carbonate decomposition?

Entropy and enthalpy do not directly affect the rate of calcium carbonate decomposition. However, they do play a role in determining the spontaneity and energy changes of the reaction, which can indirectly affect the rate. A more negative value for enthalpy, for example, would result in a faster reaction due to the release of energy.

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