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sankalpmittal
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Homework Statement
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Homework Equations
Conservation of linear momentum , when no net external force acts in a particular direction.
The Attempt at a Solution
I have already done parts (a) and (b).. So please I want assistance in parts (c) and (d). Kindly start from part (c)..
In part (a) I got u= mv/(M+m) which is the speed of the small block, when it was traveling on the vertical part of the larger mass.
In part (b) I got v1= [{(M2+Mm+m2)v2/(M+m)2} - 2gh]1/2 , which is the speed of smaller block when it breaks off the larger mass at height h.
Ok, so here is my attempt for part (c),
Extra height h' which smaller block ascends above larger mass is,
02=v12-2gh'
h'=v12/2g = {(M2+Mm+m2)v2/(M+m)22g} - h
Thus total height above ground which smaller block ascends is :
H=h+h' = {(M2+Mm+m2)v2/(M+m)22g}
But this is the wrong answer as per the book. Where did I go wrong ?
Please help !
Thanks in advance...
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