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Question about Proper Length |
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| Jul28-12, 11:39 AM | #1 |
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Question about Proper Length
I'm confused about what exactly this is, and wikipedia hasn't really helped.
It says here the proper length is the length of an object in it's rest frame. Yet it says here that "the proper length between two spacelike-separated events is the distance between the two events, as measured in an inertial frame of reference in which the events are simultaneous". If for example a train goes past a platform at a relativistic speed and an observer on the platform sees two strikes of lightning hit each end of the train simultaneously, and they're 50m apart, then what is the proper length of the train? Is it 50m because the two events are simultaneous in this frame? Or is it 50m multiplied by the lorentz factor, because this would be the value in the trains rest frame? (since for the platform observer the train appears contracted). I do not see how the two definitions are consistent and I'm not sure which one I'm supposed to use. |
| Jul28-12, 12:03 PM | #2 |
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The proper distance, or interval, between the two lightning strikes is, as your second reference says, the distance as measured in a frame in which the events are simultaneous. 50 m in this case.
The proper length of the train is measured in the object's own rest frame, 50 m * gamma in this case. |
| Jul28-12, 12:38 PM | #3 |
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To avoid confusion, I've come to prefer the less common terminology:
-rest length (of an object) - proper distance (between two events) |
| Jul28-12, 12:48 PM | #4 |
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Question about Proper Length |
| Jul28-12, 02:54 PM | #5 |
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I don't believe I thought about it carefully enough until I started with cosmoligcal distances and where 'proper distance' requires yet more thinking since actual distances are changing due to the expansion of space with time. Anyway, when you take a typical LENGTH measure in everyday life, you measure a LOCAL length, such as a 6 ft long piece of wood. What are you REALLY doing: Einstein must have thought about examples like that REALLY carefully. What is not obvious is that both you and the wood are 'moving' together: that is, there is no relativistic velocity between you, no relative acceleration...you are in the same frame of reference....and you take the measure between the two endpoints 'simultaneously'. That is, the opposite end of the ruler is on a fixed stationary point as you read off a length measure at the other end..…it’s a ‘simultaneous measure’. [If I ever knew that way back in college I sure had forgotten since then!] In everyday situations, if you measured that wood from some finite distance away, say using an instrument, you'd have to adjust the measure for the distance between you and the wood, but you'd likely not worry about time variations between you and either end of the wood. [The finite speed of light is a negligible factor.] What can quickly become confusing in relativity is that when observational distances are involved, or relative motion, space and time morph into each other...neither is fixed and static as in the simple case...space and time become dynamic. You have to adjust observational measurements among different frames of reference in order to make comparisons . A measure from a ‘distance’ [space,time,motion] becomes one of space and TIME. |
| Jul28-12, 04:32 PM | #6 |
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Ok, I think you guys have cleared it up for me, thanks so much :D :D
I was confused, like you have pointed out, with the distinction between measuring the distance between the two lightning strikes, and measuring the length of the train. Thanks again :) |
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