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mgh & -gmM/R increase with distance from Earth |
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| Oct24-12, 05:13 PM | #1 |
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mgh & -gmM/R increase with distance from Earth
Hi,
I know potential = mgh where g can be considered constant close to the surface of the Earth. So as we move away from the Earth the h and P increase. And taking P = 0 @ infinity then P = -GMm/r so P < 0 always and increases to 0 as you move away from the Earth. So it seems there is no potential at infinity and even less as you get closer to the Earth! Is that correct? What if for P = -Gmm/r, I put P = 0 at the surface of the Earth as it is for mgh? |
| Oct24-12, 05:16 PM | #2 |
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Mentor
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Yes. Of course, only potential differences are physically significant so you can add any arbitrary constant to your potential and thereby set your zero somewhere else.
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| Oct24-12, 05:38 PM | #3 |
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Recognitions:
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The constants that would correlate with ~ 62.53 mega-joules / kilogram and g = 9.80655 m / s2 (standard value): G = -6.674 x 10-11 N (m/kg)2 mass of earth = 5.974 x 1024 kg radius of earth = 6376 x 103 m |
| Oct29-12, 06:31 AM | #4 |
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mgh & -gmM/R increase with distance from Earth
Hi,
Thanks for the reply. I understand now and see how P can be set to 0 anywhere but always "potential increases with distance from the earth's surface." It seems strange that although potential is caused because an object is in the Earth's gravitational field, it increases as you move away from the Earth, where i would think the Earth had less influence. |
| Oct29-12, 09:49 AM | #5 |
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Recognitions:
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Gravitational potential is defined as the gravitational potential energy per unit mass, so it follows the same convention of increasing with distance from the source of the gravitational field. |
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