- #1
cragar
- 2,552
- 3
This is not homework I was wondering if I had to integrate
[itex] \frac{dx}{\sqrt{x^2-1}} [/itex]
Instead of doing the normal trig substitution what if I used
[itex] sin(u)^2-1=-cos(u)^2 [/itex] x=sin(u) dx=cos(u)du
But when I make the substitution I will get a negative sign under the radical, could I just pull it out as i and then some how extract the real part. How would I do it with the i in their.
[itex] \frac{dx}{\sqrt{x^2-1}} [/itex]
Instead of doing the normal trig substitution what if I used
[itex] sin(u)^2-1=-cos(u)^2 [/itex] x=sin(u) dx=cos(u)du
But when I make the substitution I will get a negative sign under the radical, could I just pull it out as i and then some how extract the real part. How would I do it with the i in their.