- #1
Palindrom
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I'm trying to see why H^n is not homeo. to R^n.
I'm now having doubts on whether this is at all true.
Is it? If not, why not?
*By H^n I mean the closed "upper" space, i.e. x_n>=0.
I'm now having doubts on whether this is at all true.
Is it? If not, why not?
*By H^n I mean the closed "upper" space, i.e. x_n>=0.