- #36
vijay123
- 122
- 0
see, here's how i did it...2^log2/3x^log2=(9x)^log3
((2^log2)/(3^log3))^(1/log6)=3x
2^log(6)2/3^log(6)3=3x
2/3=3x
x=2/9
((2^log2)/(3^log3))^(1/log6)=3x
2^log(6)2/3^log(6)3=3x
2/3=3x
x=2/9
is a bit confusing. Since, there are 2 ways to read it.b) (2/3x)^(log2) = (9x)^(log3)
No, this is not correct.vijay123 said:omg...how do you show that 2^(log2/log6)=2, by the case above...